The range that the amount withheld vary if the weekly wages, after subtracting withholding allowances, vary from $600 to $700 inclusive is: 76.35<x<101.35.
<h3>Range</h3>
Given
592<x1317
74.35+.25
Hence:
Lowest range
74.35+.25(600-592)
74.35+.25(8)
74.35+2
=76.35
Highest range
74.35+.25(700-592)
74.35+.25(108)
74.35+27
=101.35
Range
76.35<x<101.35
Therefore the range that the amount withheld vary if the weekly wages, after subtracting withholding allowances, vary from $600 to $700 inclusive is: 76.35<x<101.35.
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Answer:
h = 590
Step-by-step explanation:
To find x, rearrange the equation to where h is on its own side.
<u>Rearranged equation:</u>
Since 169 added to h was to find 769, 169 subtracted from 759 represents h.
<u>Solve:</u>
590 = h.
The Vertex of f(x)=|5x|+2 is (0,2)
and vertex of f(x)=|5x|-2 is (0,-2)
The answer is -2.76.
Hope I Helped (=^-^=)
