Hello,
Let's assume a,b,c the 3 numbers
a+b+c=62
b=a-4
c=4*a
==>a+(a-4)+4a=62
==>6a=66
==>a=11
b=11-4=7
c=4*11=44
The 3 numbers are 11;7;44
Proofs:
11+7+44=62
7=11-4
44=4*11
Answer:

Step-by-step explanation:
The formula for the sequence
is used to find the
th term of the sequence.
To find the fourth term, substitute
:

Answer:
The answer is the 1st one
Step-by-step explanation:
I risked my answer lucky for you i got it right :)
Answer:
(-4,6)
Step-by-step explanation:
y=6
5x+5(6)=10
5x+30=10
5x=-20
x=-4
(x,y)
(-4,6)
Step-by-step explanation:
x² + 3x + 2
x² + x + 2x + 2 because 1+2=3 and 2×1=2
By taking out common terms, we get
x(x+1)+2(x+1)
(x+1)(x+2)