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natulia [17]
3 years ago
6

Consider the linear system of equations. y = –x + 9 y = 0.5x – 6 If the solution is (a,–1), what is a? a =

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
8 0

Answer:

The value of a is 10.

Step-by-step explanation:

We are given with the following pair of the linear system of equations below;

y = -x+9  and   y = 0.5x-6.

Also, the solution is given as (a, -1).

To find the value of 'a', we have to substitute the solution in the equation because it is stated that (a, -1) is the solution of the given two equations.

So, the x coordinate value of the solution is a and the y coordinate value of the solution is (-1).

First, taking the equation;

y = -x+9

Put the value of x = a and y = -1;

(-1) = -(a) + 9

a = 9 + 1 = 10

Now, taking the second equation;

y = 0.5x-6

Put the value of x = a and y = -1;

(-1) = 0.5(a)-6

0.5a = 6 - 1

0.5a = 5

a=\frac{5}{0.5}

a = 10

Since we get the value of a = 10 from the equations, so the value of a is 10.

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a) The percentage of athletes whose GPA more than 1.665 is 87.49%.

b) John's GPA is 3.645.

Step-by-step explanation:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 2.7, \sigma = 0.9

a)Find the percentage of athletes whose GPA more than 1.665.

This is 1 subtracted by the pvalue of Z when X = 1.665. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.665 - 2.7}{0.9}

Z = -1.15

Z = -1.15 has a pvalue of 0.1251

1 - 0.1251 = 0.8749

The percentage of athletes whose GPA more than 1.665 is 87.49%.

b) John's GPA is more than 85.31 percent of the athletes in the study. Compute his GPA.

His GPA is X when Z has a pvalue of 0.8531. So it is X when Z = 1.05.

Z = \frac{X - \mu}{\sigma}

1.05 = \frac{X - 2.7}{0.9}

X - 2.7 = 1.05*0.9

X = 3.645

John's GPA is 3.645.

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