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belka [17]
3 years ago
8

Determine the distance between point (x1, y1) and point (x2, y2), and assign the result to pointsdistance. the calculation is: d

istance=(x2−x1)2+(y2−y1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√distance=(x2−x1)2+(y2−y1)2 you may declare additional variables. ex: for points (1.0, 2.0) and (1.0, 5.0), pointsdistance is 3.0.
Mathematics
1 answer:
taurus [48]3 years ago
5 0
For this case what you should know is that the distance between two points can be thought of as a line. To find the length of this line, you can use the formula:
 d: √ [(x2 - x1) ^ 2 + (y2 - y1) ^ 2]
 Example,
 for points (1.0, 2.0) and (1.0, 5.0):
 d: √ [(1 - 1) ^ 2 + (5 - 2) ^ 2]
 d: 3.0
 Answer:
 the distance between point (x1, y1) and point (x2, y2) is:
 d: √ [(x2 - x1) ^ 2 + (y2 - y1) ^ 2]
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Answer:

see explanation

Step-by-step explanation:

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Given the perimeter = 36 units , then

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11x = 33 ( divide both sides by 11 )

x = 3

Then

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Black_prince [1.1K]
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Answer:

P(M4\ n\ V) = 2.083\%

Step-by-step explanation:

Given

Paper = 20 slips

Word: PENNSYLVANIA

Required

Determine P(Multiple of 4 and V)

The sample size of the 20 slips is:

n(S) = 20

The outcomes of multiples of 4 is:

M4= \{4,8,12,16,20\}

n(M4) = 5

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Pr(M4) = \frac{5}{20}

Pr(M4) = \frac{1}{4}

The sample size of PENNSYLVANIA is:

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The outcome of V is:

n(V) = 1

So, the probability of V is:

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So, the required probability is: P(Multiple of 4 and V)

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P(M4\ n\ V) = \frac{1}{4} * \frac{1}{12}

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P(M4\ n\ V) = 0.02083

Express as percentage

P(M4\ n\ V) = 0.02083 * 100\%

P(M4\ n\ V) = 2.083\%

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