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grandymaker [24]
3 years ago
8

Please help!! i’ll give brainly

Mathematics
2 answers:
Anni [7]3 years ago
8 0

Answer:

1: y = 3x + 1 Swap sides so that all variable terms are on the left hand side. 3x + 1 = y Subtract 1 from both sides.

2: y(x) = 5x, y(x) is just another way of writing the equation to indicate that y is a function of x. You could simply write it as y = 5x. Thus if we compare to the standard form equation y = ax + b, a=5 and b=0. Thus the y-intercept is zero.

3: the answer is simply 0

4:  y-(1/5*x-10)=0  

STEP

1

:

           1

Simplify   —

           5

Equation at the end of step

1

:

        1          

 y -  ((— • x) -  10)  = 0  

        5          

STEP

2

:

Rewriting the whole as an Equivalent Fraction

2.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  5  as the denominator :

         10     10 • 5

   10 =  ——  =  ——————

         1        5    

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

x - (10 • 5)     x - 50

————————————  =  ——————

     5             5    

Equation at the end of step

2

:

      (x - 50)

 y -  ————————  = 0  

         5    

STEP

3

:

Rewriting the whole as an Equivalent Fraction :

3.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  5  as the denominator :

         y     y • 5

    y =  —  =  —————

         1       5  

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

y • 5 - ((x-50))     5y - x + 50

————————————————  =  ———————————

       5                  5      

Equation at the end of step

3

:

 5y - x + 50

 ———————————  = 0  

      5      

STEP

4

:

When a fraction equals zero :

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Hope this helps :)

Naily [24]3 years ago
5 0
The answer is choice c
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Find x, y, and z such that x³+y³+z³=k, for each k from 1 to 100.​
love history [14]

Answer:

x3+y3+z3=k  with k is integer from 1 to 100

solution x=0 , y=0 and z=1 and k= 1

For K= 1 , we have the following solutions (x,y,x) = (1,0,0) ; or (0,1,0) ; or (0,0,1) ,

For k =1 also (9,-8,-6) or (9,-6,-8) or (-8,-6,9) or (-8,9,-6) or (-6,-8,9) or (-6,9,8)

And (-1,1,1) or (1,-1,1)

=>(x+y)3−3x2−3xy2+z3=k

=>(x+y+z)3−3(x+y)2.z−3(x+y).z2=k

=>(x+y+z)3−3(x+y)z[(x+y)−3z]=k

lety=αand z=β

=>x3=−α3−β3+k

For k= 2 we have (x,y,z) = (1,1,0) or (1,0,1) or (0,1,1)

Also for (x,y,z) = (7,-6,-5) or (7,-6,-5) or (-6,-5,7) or (-6,7,-5) or (-5,-6,7) or (-5,7,-6)

For k= 3 we have 1 solution : (x,y,z) = (1,1,1)

For k= 10 , we have the solutions (x,y,z) = (1,1,2) or (1,2,1) or (2,1,1)

For k= 9 we have the solutions (x,y,z) = (1,0,2) or (1,2,0) or (0,1,2) or (0,2,1) or (2,0,1) or (2,1,0)

For k= 8 we have (x,y,z) = ( 0,0,2) or (2,0,0) or (0,2,0)

For k= 17 => (x,y,z) = (1,2,2) or (2,1,2) or ( 2,2,1)

For k = 24 we have (x,y,z) = (2,2,2)

For k= 27 => (x,y,z) = (0,0,3) or (3,0,0) or (0,3,0)

for k= 28 => (x,y,z) = (1,0,3) or (1,3,0) or (1,3,0) or (1,0,3) or (3,0,1) or (3,1,0)

For k=29 => (x,y,z) = (1,1,3) or (1,3,1) or (3,1,1)

For k = 35 we have (x,y,z) = (0,2,3) or (0,3,2) or (3,0,2) or (3,2,0) or 2,0,3) or (2,3,0)

For k =36

we have also solution : x=1,y=2andz=3=>

13+23+33=1+8+27=36 with k= 36 , we have the following

we Have : (x, y,z) = (1, 2, 3) ; (3,2,1); (1,3,2) ; (2,1,3) ; (2,3,1), and (3,1,2)

For k= 43 we have (x,y,z) = (2,2,3) or (2,3,2) or (3,2,2)

For k = 44 we have ( 8,-7,-5) or (8,-5,-7) or (-5,-7,8) or ( -5,8,-7) or (-7,-5,8) or (-7,8,-5)

For k =54 => (x,y,z) = (13,-11,-7) ,

for k = 55 => (x,y,z) = (1,3,3) or (3,1,3) or (3,1,1)

and (x,y,z) = (10,-9,-6) or (10,-6,-9) or ( -6,10,-9) or (-6,-9,10) or (-9,10,-6) or (-9,-6,10)

For k = 62 => (x,y,z) = (3,3,2) or (2,3,3) or (3,2,3)

For k =64 => (x,y,z) = (0,0,4) or (0,4,0) or (4,0,0)

For k= 65 => (x,y,z) = (1,0,4) or (1,4,0) or (0,1,4) or (0,4,1) or (4,1,0) or (4,0,1)

For k= 66 => (x,y,z) = (1,1,4) or (1,4,1) or (4,1,1)

For k = 73 => (x,y,z) = (1,2,4) or (1,4,2) or (2,1,4) or (2,4,1) or (4,1,2) or (4,2,1)

For k= 80=> (x,y,z)= (2,2,4) or (2,4,2) or (4,2,2)

For k = 81 => (x,y,z) = (3,3,3)

For k = 90 => (x,y,z) = (11,-9,-6) or (11,-6,-9) or (-9,11,-6) or (-9,-6,11) or (-6,-9,11) or (-6,11,-9)

k = 99 => (x,y,z) = (4,3,2) or (4,2,3) or (2,3,4) or (2,4,3) or ( 3,2,4 ) or (3,4,2)

(x,y,z) = (5,-3,1) or (5,1,-3) or (-3,5,1) or (-3,1,5) or (1,-3,5) or (1,5,-3)

=> 5^3 + (-3)^3 +1 = 125 -27 +1 = 99 => for k = 99

For K = 92

6^3 + (-5)^3 +1 = 216 -125 +1 = 92

8^3 +(-7)^3

Step-by-step explanation:

4 0
3 years ago
a coin bank holds nickels, dimes, and quarters. there are 54 coins in the bank and the value of the coins is $4.75. if there are
TEA [102]
Not possible, you know you have to have at least 5 nickels so substract those first, now your at 4.50.  you cant get to 54 coins after that
7 0
3 years ago
i forgot how to find equivalent fractions. i know that the bottom would be times by 3 to get 18 but if you times 3 by 3 it would
tester [92]
Set up a proportion.  take 3/6 = 20/x
Cross multiply 3 * x = 6 * 20
Simplify  3x = 120
Divide by 3  x = 40
So the denominator of the bottom fraction is 40
6 0
3 years ago
Read 2 more answers
. Could someone please explain this to me in detail. I am very confused. Thank you so much!. . A candle is 17 inches tall after
andrew-mc [135]

The generic equation of the line is:

H-H0 = m (T-T0)

Where,

m: slope of the line

(T0, H0): ordered pair belonging to the line.

The slope of the line is:

m =\frac{H2-H1}{T2-T1}

Substituting values we have:

m =\frac{15-17}{5-3}

Rewriting:

m =\frac{-2}{2}

m = -1

Then, choosing an ordered pair we have:

(T0, H0) :( 5, 15)

Substituting values we have:

H-15=-(T-5)

Rewriting the equation:

H-15=-T+5

H=-T+5+15

H=-T+20

Then, for 8 hours we have:

H=-8+20

H=12

Answer:

a linear equation to model the relationship between height H of the candle, and T time is:

H=-T+20

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7 0
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UNO [17]
The answer would be
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