#1 is A and #2 is 24 I think
Rectangle diagonals are equal.
2(5a+1) = 2(a+1)
10a + 2 = 2a + 2
10a -2a = 2 - 2
8a = 0
⇒ a = 0
AC = 2(5a+1) = 2(5 × 0 +1)= 2(0 + 1) = 2 × 1 = 2 <span>
</span>BD = 2(a+1) = 2(0 + 1) = 2 <span>× 1 = 2
</span>
Ansver: AC = BD = 2
5 goes into 62 12 times with a remainder of 2. So technically 62 divided by 5 is 12.4.
Hope this helps!
11
(9, 18, 27, 36, 45, 54, 63, 72, 81, 90 and 99)
Those numbers divisible by 9 are the multiple of 9; thus need to know how many multiples of 9 there are between 1 and 100:
100 ÷ 9 = 11 r 1 ÷ last multiple of 9 is 11 × 9 (= 99)
→ There are 11 - 1 + 1 = 11 numbers between 1 and 100 which are divisible by 9.
(They are 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99.)
Answer:
3/-2
Step-by-step explanation:
(3x) km/3 -2x=4 (x3) times 3 on both sides because you need to get the x by itself and your dividing so the opposite of dividing is multiplying.
9km - 2x = 12
-9 -9 subtract on both sides
-2x = 3
-2 -2 divide on both sides.
so x= 3/-2
I'm in algebra too, and i'm relearning it, so hope i have helped you in anywy and if i haven't I'm sorry.
