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3 years ago

Solve by graphing : -x + 3y = -9 y = -x + 1

Mathematics

1 answer:

mafiozo [28]3 years ago

7 0

Step-by-step explanation:

the answer from the graph is;

(3 , -2)

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∠A is complementary to ∠B. The measure of ∠A is (8x+12)∘. The measure of ∠B is half the measure of ∠A.

Alex777 [14]

Answer:

Step-by-step explanation:

(Divide the entire Angle A by 2)

4 0

3 years ago

Read 2 more answers

Solve the system of equations -x-2y=0 and -x+y=6 by combining the equations

Elden [556K]

Answer:

x=-4 and y=10

Step-by-step explanation:

Use the second equation to make y=x+6

sub y=x+6 into the first equation

-x-2*(x+6)=0

-x-2x-12=0

-3x-12=0

3x=-12

x=-4

Now sub x=-4 into the second equation

-(-4)+y=6

y=6+4

y=10

3 0

3 years ago

There are two cameras that take pictures of a traffic intersection. Camera A starts taking pictures at 6 AM and takes a picture

Scilla [17]

Answer:

41 minutes before noon

Step-by-step explanation:

The given parameters are;

The time camera A starts taking pictures = 6 AM

The frequency of picture taking by camera A = Once every 11 minutes

The time camera B starts taking pictures = 7 AM

The frequency of picture taking by camera B = Once every 7 minutes

The number of times both cameras take a picture at the same time before noon = 4 times

Let the time the two cameras first take a picture the same time be x, we have;

11·y - 60 = x

7·z = x

Taking the number of times after 7 camera A snaps and noting that the first snap is 6 minutes after 7, we have

11·b + 6 = x

7·z = x

x is a factor of 7 and 11·b + 6 and x is some minutes after 7

By using Excel, to create a series of values for Camera A based, on 11·b + 6, and dividing the results by 7 we have the factors of 7 at;

28, 105, 182, and 259 minutes after 7

Given that there are 60 minutes in one hour, we have;

259/60 = 4 hours 19 minutes, which is 11:19 a.m. or 41 minutes before noon.

4 0

3 years ago

Find the interquartile range for a data set having the five-number summary: 3.4, 10.8, 16.7, 23.1, 31.5

natita [175]

.Answer:

D. 12.3

Step-by-step explanation:

Arrange the data in increasing order

3.4, 10.8, 16.7, 23.1, 31.5

⇒This is an odd set of numbers, to find the interquartile range you include the median in both quartiles.

Locate the median/center value

3.4, 10.8, 16.7, 23.1, 31.5

Find lower half and find the median

lower half values⇒3.4, 10.8, 16.7

Median=Q1=10.8

Find the upper half and find

upper half= 16.7,23.1, 31.5

median= 16.7,23.1,31.5

Q3=23.1

Interquartile range=Q3-Q1

23.1-10.8=12.3

5 0

3 years ago

(a) Suppose one house from the city will be selected at random. Use the histogram to estimate the probability that the selected

Lera25 [3.4K]

Answer:

a. 0.71

b. 0.9863

Step-by-step explanation:

a. The mean of the distribution is given as $403,000 and the standard deviation is $278,000.

-To estimate the probability that a randomly selected house has a value less than $500,000:

$P(X$

Thus, the probability that a randomly selected house has a value less than $500,000 is 0.71

b. -since 40 is larger than or equal to 30, we assume normal distribution.

-The probability can therefore be calculated as:

$P(\bar X)=P(z$

Hence, the probability that the mean value of the 40 houses is less than $500,000 is 0.9863

3 0

3 years ago