Hi there
First find the rate of growth between
1992 and 1998
The formula is
P=Ae^rt
P the population in 1998. (76 million)
A the population in 1992 (72 million)
E constant
R rate of growth?
T time 1,998−1,992=6 years
We need to solve for r
R=[log (p/A)÷log (e)]÷t
R=(log(76÷72)÷log(e))÷6
R=0.009
Now find the population in 2012
P=Ae^rt
P ?
A 72 million
R 0.009
T 2,012−1,992=20 years
So
P=72×e^(0.009×20)
P=86.2 round your answer to get
P=86 million
Good luck!
Using it's concept, it is found that the sample proportion for this population is of 0.4.
- The estimate of the <em>sample proportion for a population</em> is given by the <u>number of desired outcomes divided by the size of the sample</u>.
In this problem:
- 1,599 of those surveyed responded in favor of the park.
- The sample size is of 4,000.
Hence:

The sample proportion for this population is of 0.4.
A similar problem is given at brainly.com/question/14510808
Answer:
1 one
Step-by-step explanation: just know
Zero of 7 with a multiplicity of 3 means one factor is 
Zero of -1 with a multiplicity of 2 means one factor is 
Zero of 5 with a multiplicity of 1 means one factor is 
Multiplying, we get

That's already in factored form so we leave it here.