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frutty [35]
3 years ago
14

Put the following fractions from greatest to least 7/6,3/4,11/12

Mathematics
2 answers:
poizon [28]3 years ago
6 0
3/4, 7/6, 11/12

Comment if you need an explanation as to why :)
lakkis [162]3 years ago
3 0
First, you should convert the fraction to decimals to make it easier to order.

7 / 6 ≈ 1.2

3 / 4 = 0.75

11 / 12 = 0.9

Now order
1.2, 0.9, 0.75
      or 
7/6, 11/12, 3/4
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Let g' be the group of real matricies of the form [1 x 0 1]. Is the map that sends x to this matrix an isomorphism?
aliina [53]

Yes. Conceptually, all the matrices in the group have the same structure, except for the variable component x. So, each matrix is identified by its top-right coefficient, since the other three entries remain constant.

However, let's prove in a more formal way that

\phi:\ \mathbb{R} \to G,\quad \phi(x) = \left[\begin{array}{cc}1&x\\0&1\end{array}\right]

is an isomorphism.

First of all, it is injective: suppose x \neq y. Then, you trivially have \phi(x) \neq \phi(y), because they are two different matrices:

\phi(x) = \left[\begin{array}{cc}1&x\\0&1\end{array}\right],\quad \phi(y) = \left[\begin{array}{cc}1&y\\0&1\end{array}\right]

Secondly, it is trivially surjective: the matrix

\phi(x) = \left[\begin{array}{cc}1&x\\0&1\end{array}\right]

is clearly the image of the real number x.

Finally, \phi and its inverse are both homomorphisms: if we consider the usual product between matrices to be the operation for the group G and the real numbers to be an additive group, we have

\phi (x+y) = \left[\begin{array}{cc}1&x+y\\0&1\end{array}\right] = \left[\begin{array}{cc}1&x\\0&1\end{array}\right] \cdot \left[\begin{array}{cc}1&y\\0&1\end{array}\right] = \phi(x) \cdot \phi(y)

8 0
3 years ago
8×4=(A×7)-(A×3)<br>what is the value of A in the equation shown??​
Pani-rosa [81]

Answer:

Step-by-step explanation:

8×4 = (A×7) - (A×3) = A(7-3) = A×4

A = 8

4 0
3 years ago
WILL MARK BRAINLIST
iren [92.7K]

Answer:

See below.

Step-by-step explanation:

1/2 = shrink by a factor of 1/2.

+7 = moved up 7 units.

8 0
3 years ago
Simplify  ( √ 5 ) ( 3 √ 5 )
Amiraneli [1.4K]

Answer:

5^\frac{5}{6}

Step-by-step explanation:

\sqrt{5} can be represented as 5^{\frac{1}{2}} and \sqrt[3]5} can be represented as 5^{\frac{1}{3}}. Therefore, the expression can be rewritten as:

5^{\frac{1}{2}}*5^{\frac{1}{3}}

The rule for multiplying two exponents with the same base is you add the exponents. For example: x^m*x^k=x^{m+k}

We can use the same property to get:

5^{\frac{1}{2} +\frac{1}{3}}

which is just 5^\frac{5}{6} after you add the fractions

8 0
3 years ago
Help help help help help help help help
serg [7]
The answer should be hid
6 0
3 years ago
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