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Fantom [35]
3 years ago
12

Please I Dont Have A Lot of Time what is the median, mode, mean, and range

Mathematics
2 answers:
notsponge [240]3 years ago
7 0

Answer:

(Shown below)

Step-by-step explanation:

The Mean, AKA the average is all of the numbers added up, then divided by how many numbers there were. For example, take this data set:

3, 5, 10, 6, 5, 5

We add up all of the numbers:

3 + 5 + 10 + 6 + 1 + 5 + 5 = 35

Now, we divide by how many numbers there were. Since there were 7 numbers, we do:

\frac{35}{7} = 5

Therefore, 5 is our Mean.

Next up, the Median. Median is just the number in the middle of the data set, but we have to put it from least to greatest. Here it is again:

3, 5, 10, 6, 1, 5, 5

1, 3, 5, 5, 5, 6, 10

As you can see, the 5 is in the middle, so it is our Median.

Now the Mode. The Mode is number that occurs most often. Again, it's easier to put the numbers from least to greatest. The data set:

3, 5, 10, 6, 1, 5, 5

1, 3, 5, 5, 5, 6, 10

So, the 5 is the Mode because it occurs thrice, while the other numbers only occur once. Remember the Mode is what the number is, not how many times it repeats.

Lastly, the Range. The Range is just the difference of the largest number to the smallest number. This one also requires to be from least to greatest.

1, 3, 5, 5, 5, 6, 10

10 - 1 = 9

Therefore, the Range of the data set is 9. I hope this helps you!

Mademuasel [1]3 years ago
4 0
Median is middle number mean is the most common number and range is the difference between the smallest and biggest number
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The national mean annual salary for a school administrator is $90,00 a year (The Cincinnati Enquirer, April 7, 2012). A school o
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Answer:

a) Null hypothesis:\mu = 90000  

Alternative hypothesis:\mu \neq 90000  

b) p_v =2*P(t_{(24)}  

c) If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean for the salary differs from 9000 at 5% of significance.

Step-by-step explanation:

1) Data given and notation  

77600 ,76000 ,90700 ,97200 ,90700 ,101800 ,78700 ,81300 ,84200 ,97600 ,

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We can calculate the sample mean and deviation with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

The values obtained are:

\bar X=85272 represent the mean annual salary for the sample  

s=11039.23 represent the sample standard deviation for the sample  

n=25 sample size  

\mu_o =90000 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean salary differs from 90000, the system of hypothesis would be:  

Null hypothesis:\mu = 90000  

Alternative hypothesis:\mu \neq 90000  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b: Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{85272-90000}{\frac{11039.23}{\sqrt{25}}}=-2.141    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=25-1=24  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(24)}  

Part c: Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean for the salary differs from 9000 at 5% of significance.

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