Answer:
0.768 kg
Explanation:
Step 1: Given data
- Mass of ammonium nitrate (solute): 27.8 g
- Molality of the solution (m): 0.452 m
Step 2: Calculate the moles corresponding to 27.8 g of ammonium nitrate
The molar mass of ammonium nitrate is 80.04 g/mol.
Step 3: Calculate the mass of water
The molality is equal to the moles of solute divided by the kilograms of solvent (water).
Answer:
1.06 × 10^5 J
Explanation:
We have to use the formula;
log(k2/k1) = Ea/2.303 ×R (1/T1 - 1/T2)
Given that;
k1 = 1.10 × 10-4 s-1
k2= 1.02 × 10-3 s-1
Ea=?
R=8.314 Jmol-1K-1
T1= 470. °C
T2= 510. °C
Hence;
log(1.02 × 10-3 s-1/1.10 × 10-4 =Ea/2.303 ×8.314(1/470 -1/510)
0.9672 = Ea/19.122(2.13 - 1.96) × 10^-3
0.9672= Ea/19.122(0.17) × 10^-3
0.9672= 1.7 ×10^-4 Ea/19.122
19.122 × 0.9672 = 1.74 × 10^-4Ea
Ea= 19.122 × 0.9672/1.74 × 10^-4
Ea= 18.495/1.74 × 10^-4
Ea= 1.06 × 10^5 J
Answer:
alright bud lets see hmm.... the answer is a. 90.5kpa
Explanation:
92.3 kPa - 1.82 kPa = 90.5 kPa
keep up your hope also corrected me if a am wrong in anyway! :)
Explanation:
All atoms of one type were identical in mass and properties.
Option a: alkene
Styren is C6H5CH=CH2, i.e. ethenylbenzene