Given is the specific heat of water equal to 4.18 Joule per gram per *C.
This means to raise the temperature of 1 g of water by 1 degree Celsius we need 4.18 joule of energy.
Now, look at the question. We are asked that how much amount of energy would be required to raise the temperature of 25 g of water by (54-50) = 4 degree celsius.
To do so we have formula
Q = m C (temperature difference)
Have a look at pic for answer
Answer:
<em>17500 calories</em> of chocolate bars are needed to eat to gain 5 pounds.
Explanation:
We can use ratios to calculate the answer using the information given in the question.
1 pound : 3500 grams
5 pounds : x grams
As it is given that the individual is burning no calories, we do not have to factor in any additional numbers.
<u><em>Method</em><em> </em><em>A</em><em>:</em></u>
To go from 1 in the first ratio to 5 in the second ratio, they multipled 1 by 5. Hence, to go from 3500 in the first ratio to x in the second ratio, we must multiply by 5.
x = 3500 × 5
x = 17500
<em><u>Method B</u>:</em>
To solve for the answer x, we can convert the ratios into fractions.
1 / 5 = 3500 / x
3500 / x = 1 / 5
To make x the subject, multiply the denominator of the left fraction with the numerator of the right fraction and place it on the left side. Then multiply the numerator of the left fraction with the denominator of the right fraction and place it on the right side.
x = 5 × 3500
x = 17500
<span>J.j thomson a british physicist was the first to identify the electron in 1987</span>
The molar mass of Na₂SO₄ -
2 x Na - 2 x23 = 46
1 x S - 1 x 32 = 32
4 x O - 4 x 16 = 64
total = 46 + 32 + 64 = 142 g/mol
the molarity of solution - 2.0 M
in 1 L of solution , 2.0 moles
Therefore in 2.5 L - 2 mol/L x 2.5 L = 5 mol
then the mass of Na₂SO₄ required = 142 g/mol x 5 mol = 710 g
