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3 years ago

15

Suppose the scenario of the mystery creature in the garden was a real situation. How could you apply your knowledge of classific

ation and your experience using a taxonomic key to identify the organism? Why would this process be important?

1 answer:

taurus [48]3 years ago

4 0

..............................?

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A graduated cylinder contains 17.5 ml of water. When a metal cube is placed onto the cylinder, it’s water level rises to 20.3 ml

MrRa [10]

Answer:

20.3-17.5=2.8ml 1ml=1cm3 vol= 2.8cm3

Explanation:

4 0

3 years ago

How is this equation read? <br> 4Na (1) +Mn(SO 4 ) 2 (aq) Mn (3) +2Na 2 SO

Trava [24]

The answer is A, do you want me to explain it? It’s pretty simple, you just need to follow all the signs in brackets and match them in those in the answer

7 0

3 years ago

Read 2 more answers

A tank of oxygen with a pressure of 23 atm is moved from room temperature of 293K to a storage freezer at 239K. What is the fina

Gelneren [198K]

Answer:

18.76atm

Explanation:

Using the formula V1P1/T1 = V2P2/T2, from combined gas law. Volume is constant since we have not been given. Therefore the formula comes to be; P1/T1 = P2/T1

To get P2 = T2(P1/T1)

Where P2 is final pressure

P2 = 239K ( 23atm/293K)

=18.76atm

7 0

3 years ago

if an object has a mass of 60 grams in a volume of 120 cm3 then calculate the density would this object sink or float

Ivanshal [37]

Answer: 0.5 g/cm^3

Density equals mass divided by volume so..

60/120 is 0.5 g/cm^3

7 0

2 years ago

A student estimated the volume of a liquid in a beaker as 200.0 mL. When she poured the liquid into a graduated cylinder she MEA

Taya2010 [7]

Answer:

<h3>The answer is 0.91 %</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\% \\$

From the question

actual volume = 198.2 mL

error = 200 - 198.2 = 1.8

So we have

$P(\%) = \frac{1.8}{198.2} \times 100 \\ = 0.90817356205...$

We have the final answer as

<h3>0.91 %</h3>

Hope this helps you

6 0

3 years ago