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3 years ago

Explain Charles law

Chemistry

1 answer:

kodGreya [7K]3 years ago

8 0

"Charles Law" is the relationship between "volume-temperature" (V ∝ T).

<u>Explanation</u>:

Charles Law is basically volume-temperature relationship (V ∝ T). French scientist “Jacques Charles” in 1787 studied effect of temperature on the volume of gases at constant pressure, which described how gases manage to expand when heated. Law stated as “At constant pressure, the volume of a given "mass" of a gas decreases or increases by 1/273 of its volume at $0^{\circ} \mathrm{C}$ for each one degree rise or fall in temperature”. Formula derived from law is as follows: $\mathbf{V}_{\mathbf{t}}=\mathbf{V}_{0}[\mathbf{1}+\mathbf{t} / \mathbf{2} 7 \mathbf{3}]$ here ${V}_{0}$ is volume of given mass of a gas at $0^{\circ} \mathrm{C}$ , ${V}_{t}$ is its volume at any temperature $t^{\circ} \mathrm{C}$ . Application of Charles law is hot air balloons.

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**98 POINTS**

Andrei [34K]

OP already did it - CONGRATS!!

here are the steps 2 get the same ans:

(NH4)2 CO3 has 2x N, 8x H, 1x C and 3x O per molecule

so its molecular mass = 2x14 + 8x1 + 1x12 + 3x16

=28+8+12+48

=96g

of that 96g, 8x1=8g is due to Hydrogen

so by ratio n proportion, 1.00g will have 1x8/96 = 1/12g = 0.083g of H

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3 years ago

Material of density of 762 kg/m3 occupies a container

konstantin123 [22]

Answer:

The answer is

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

density = 762 kg/m³

We must first convert the volume from cm³ to m³

$1 \: {cm}^{3} = 1 \times {10}^{ - 6} {m}^{3}$

So 99 cm³ will be

$9.9 \times {10 }^{ - 5} \: \: {m}^{3}$

So the mass of the material is

$mass = 762 \times 9.9 \times {10}^{ - 5} \\ = 0.075438$

We have the final answer as

Hope this helps you

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4 years ago

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babymother [125]

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4 years ago

Co(g) + 2 h2 --> ch3oh 2.50 g of hydrogen is reacted with 30.0 l of carbon monoxide at stp. 1. what is the limiting reactant?

Lemur [1.5K]

CO(g) +2H2--->CH3OH
2.50g H2*1mol/2g=1.25 mol H2
30.0L CO*1mol/22.4L=1.34 mol CO,
according to reaction 1 mol CO needs 2 mol H2,so 1.34 mol CO need 2.68 mol H2, so 1) limiting teactant is H2 (H)

2)1.25 mol CH3OH will be produced, 1.25 mol*32g/mol=40.0 g CH3OH
3) 1.25 mol H2 needs 0.625 g CO
1.34-0.625=0.715 g CO leftover

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3 years ago

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Explain Charles law​

Explain Charles law