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Tju [1.3M]
2 years ago
6

I don't really understand 1 step equations...can anyone explain with an example?

Mathematics
1 answer:
jek_recluse [69]2 years ago
3 0
You will only need to perform one step<span> in order to solve the </span>equation<span>. </span>One<span> goal in solving an </span>equation<span> is to have only variables on </span>one<span> side of the equal sign and numbers on the other side of the equal sign. The other goal is to have the number in front of the variable equal to </span>one<span>.</span>
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Type the correct answer in each box. Use numerals instead of words.
lubasha [3.4K]

Answer:

System A has 4 real solutions.

System B has 0 real solutions.

System C has 2 real solutions

Step-by-step explanation:

System A:

x^2 + y^2 = 17   eq(1)

y = -1/2x            eq(2)

Putting value of y in eq(1)

x^2 +(-1/2x)^2 = 17

x^2 + 1/4x^2 = 17

5x^2/4 -17 =0

Using quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a = 5/4, b =0 and c = -17

x=\frac{-(0)\pm\sqrt{(0)^2-4(5/4)(-17)}}{2(5/4)}\\x=\frac{0\pm\sqrt{85}}{5/2}\\x=\frac{\pm\sqrt{85}}{5/2}\\x=\frac{\pm2\sqrt{85}}{5}

Finding value of y:

y = -1/2x

y=-1/2(\frac{\pm2\sqrt{85}}{5})

y=\frac{\pm\sqrt{85}}{5}

System A has 4 real solutions.

System B

y = x^2 -7x + 10    eq(1)

y = -6x + 5            eq(2)

Putting value of y of eq(2) in eq(1)

-6x + 5 = x^2 -7x + 10

=> x^2 -7x +6x +10 -5 = 0

x^2 -x +5 = 0

Using quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a= 1, b =-1 and c =5

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(1)(5)}}{2(1)}\\x=\frac{1\pm\sqrt{1-20}}{2}\\x=\frac{1\pm\sqrt{-19}}{2}\\x=\frac{1\pm\sqrt{19}i}{2}

Finding value of y:

y = -6x + 5

y = -6(\frac{1\pm\sqrt{19}i}{2})+5

Since terms containing i are complex numbers, so System B has no real solutions.

System B has 0 real solutions.

System C

y = -2x^2 + 9    eq(1)

8x - y = -17        eq(2)

Putting value of y in eq(2)

8x - (-2x^2+9) = -17

8x +2x^2-9 +17 = 0

2x^2 + 8x + 8 = 0

2x^2 +4x + 4x + 8 = 0

2x (x+2) +4 (x+2) = 0

(x+2)(2x+4) =0

x+2 = 0 and 2x + 4 =0

x = -2 and 2x = -4

x =-2 and x = -2

So, x = -2

Now, finding value of y:

8x - y = -17    

8(-2) - y = -17    

-16 -y = -17

-y = -17 + 16

-y = -1

y = 1

So, x= -2 and y = 1

System C has 2 real solutions

4 0
3 years ago
Read 2 more answers
Which shows a reflection of the triangle?
lora16 [44]
C, or the last photo, shows a reflection.
4 0
3 years ago
Read 2 more answers
L –3 |<br><br><br> A. 3<br><br> B. -3<br><br> C. 0.30<br><br> D. 30
Vesnalui [34]

Answer:

| -3 | = 3

Step-by-step explanation:

minus is removed

7 0
3 years ago
3.2] I can rearrange formulas to solve for a specified variable.<br><br> Solve for r.<br> h=r-m
Lesechka [4]

Answer:

r = h + m

Step-by-step explanation:

h = r - m

Switch sides.

r - m = h

Add m to both sides.

r - m + m = h + m

Simplify the left side. -m + m = 0

r = h + m

6 0
1 year ago
What is slope in urebcirbicrbcrc
valina [46]

Answer:

if u put that in latin then in spanish then back in english then someone might actually be able to answer that

Step-by-step explanation:

4 0
2 years ago
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