Answer:
The equillibrium constant Kc = 11.2233
Explanation:
Step 1:
aA + bB ⇔ cC + dD
with a, b, c and d = coefficients
Kc = equillibrium constant =( [C]^c [D]^d ) / ( [A]^a [B]^b)
Concentration at time t
[A] = 0.300 M
[B] =1.10 M
[C] = 0.450 M
Change :
A: -x
B: -2x
C: -x
The following reaction occurs and equillibrium is established
A + 2B ⇔ C
[A] = 0.110M
[B] = ?
[C] = 0.640 M
For A we see that after change: 0.3 -x = 0.11
Then for B we have 1.1 - 2x = ? ⇒ 1.1 -2 *0.19 = 0.72
This gives us for the equillibrium constant Kc = [C] / [A][B] ²
Kc = 0.64 / (0.11) * (0.72)² = 11.2233
This is physic.
because heat transfers from the hotter things to the cooler things
Explanation:
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sorry I don't have any ideas
Answer:
(a) 140 years
(b) 3.125 pounds
Explanation:
<u>QuestIons</u>
(a) How long is five half-life
(b) How much radioactive strontium is left after five half-life
Given that:
Half-life is about 28 years; &
There are 100 pounds of this radioactive waste
Five half-life will be;
= 28 × 5
= 140 years
The amount of radioactive remaining after five half-life is:
= 100 × 0.03125
= 3.125 pounds
Hey there!
Mg + HCl → MgCl₂ + H₂
Balance Cl.
1 on the left, 2 on the right. Add a coefficient of 2 in front of HCl.
Mg + 2HCl → MgCl₂ + H₂
Balance H.
2 on the left, 2 on the right. Already balanced.
Balance Mg.
1 on the left, 1 on the right. Already balanced.
Our final balanced equation: Mg + 2HCl → MgCl₂ + H₂
Hope this helps!
