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3 years ago

What happens when an electron absorbs energy?

Chemistry

1 answer:

qaws [65]3 years ago

5 0

Answer:

Explanation:

this is because the electrons are attracted to the protons, the stronger the attraction and energy level the closer the electrons are to the nucleus. this moves them to a higher energy orbital. For example in a Bohr diagram.

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Gaseous ethane CH3CH3 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. What is the

ololo11 [35]

Answer:

46.97g

Explanation:

Hello,

To find the theoretical yield, we must first of all get the equation of reaction right in order to know how the compounds combine together.

Equation of reaction;

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

From the equation of reaction,

2 moles of C₂H₆ reacts with 7 moles of O₂ to produce 4 moles of CO₂.

Number of moles = mass / molar mass

Mass = number of moles × molar mass

Mass of CO₂ = 4 × 44 = 176g

Mass of C₂H₆ = 2 × 30 = 60g

Mass of O₂ = 7 × 32 = 224g

Therefore, 224g + 60g (O₂ + C₂H₆) = 176g of CO₂.

284g of reactants = 176g of product(CO₂)

(18 + 57.8)g of reactants = x g of products(CO₂)

X = (75.8 × 176) /284

X = 46.97g of CO₂.

Theoretical yield of CO₂ is 46.97g

8 0

3 years ago

The density of an unknown metal was determined to be 2.85 g/ml. the actual density was 2.70 g/ml. what is the percent error in t

Tasya [4]

% error = $\frac{|experimental - theoretical|}{theoretical}$ x 100%

Experimental: 2.85
Actual (theoretical): 2.70

% error = $\frac{2.85-2.70}{2.70}$ x 100% = .055555 x 100% = 5.56%

7 0

3 years ago

What variables affect whether or not the fishing weight floats?

Degger [83]

Answer:

Density

Explanation:

If the fishing weight is more dense than the water, it will sink and if it less dense it will float. hope this helps :)

7 0

3 years ago

Consider the reaction:

stich3 [128]

Answer:

$\large \boxed{\text{-851.4 kJ/mol}}$

Explanation:

2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s); ΔᵣH = ?

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

$\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})$

2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s)

ΔfH°/kJ·mol⁻¹: 0 -824.3 -1675.7 0

$\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [1(-1675.7) + 2(0)] - [2(0) - 1(-824.3)]\\& = & -1675.7 + 824.3\\& = & \textbf{-851.4 kJ/mol}\\\end{array}\\\text{The enthalpy change is } \large \boxed{\textbf{-851.4 kJ/mol}}$

7 0

3 years ago

HELLLLLLLLPPPPPPPPPPPPPPPPPP

stealth61 [152]

Answer:

Explanation:

There is a lowercase a on both sides.

4 0

2 years ago