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Anna71 [15]
4 years ago
6

How did rutherford's experimental evidence lead to the development of a new atomic number

Chemistry
1 answer:
borishaifa [10]4 years ago
8 0
Rutherford's experiment was the gold foil experiment.

The gold foil experiment was him shooting alpha particles (you could think of this as a Helium atom without its electrons) into a gold foil. The whole experiment was surrounded with something called Zinc Sulfide which sparked when the alpha particles hit it.

Most of the alpha particles went through, approximately 1 in 8000 alpha particles deflected at a large angle (almost right back to where it was shot).

This constant ratio caused him to conclude that:-the atom was mostly empty space (since most alpha particles went through)-there was something very positive in the atom (the proton)-the proton was very dense (since it made something going light speed deflect back at a large angle)-The proton was also very small (since only 1 in 8000 hit it)

Prior to the discovery of the proton, John Dalton's periodic table was used. Having "elements" such as soda and potash. Now that we have discovered the proton and found out that each atom's number of protons is unique, we used that to classify each element's identity.
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ANSWER IF U LOVE UR MOM PLS
zalisa [80]

Answer:

yes

Explanation:

she loves me and i would die for her

8 0
3 years ago
Read 2 more answers
How much oxygen will contain the same number of atoms as the number of molecules in 73 g of HCI?​
expeople1 [14]

Answer:

64g of O2.

Explanation:

We'll begin by calculating the number of molecules in 73g if HCl.

This is illustrated below:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of HCl also contains 6.02×10²³ molecules

1 mole of HCl = 1 + 35.5 = 36.5g

Thus, if 36.5g of HCl contains 6.02×10²³ molecules, then 73g of HCl will contain = (73 x 6.02×10²³)/36.5 = 1.204×10²⁴ molecules.

Therefore, 73g of HCl will contains 1.204×10²⁴ molecules.

Now, we shall determine the mass of oxygen that will contain 1.204×10²⁴ molecules.

This can be obtained as follow:

1 mole of O2 = 16x2 = 32g

32g of O2 contains 6.02×10²³ molecules.

Therefore, Xg of O2 will contain 1.204×10²⁴ molecules i.e

Xg of O2 = (32 x 1.204×10²⁴)/6.02×10²³

Xg of O2 = 64g

Therefore, 64g of O2 will contain the same number of molecules (i.e 1.204×10²⁴ molecules) in 73g of HCl.

5 0
4 years ago
Please help me with this :) thank you
Marat540 [252]

Answer:

Hii

Explanation:

<em>Yo</em><em>ur</em><em> answer</em><em> is</em><em> 2</em>

<em>1</em><em>0</em><em>^</em><em>2</em><em>=</em><em>1</em><em>0</em><em>0</em>

<em>1</em><em>0</em><em>*</em><em>1</em><em>0</em><em>=</em><em>1</em><em>0</em><em>0</em>

8 0
3 years ago
A flask contains 0.83molof neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is the
blsea [12.9K]

Answer:

V = 56.72 L

Explanation:

Given data:

Number of mole of neon gas = 0.83 mol

Temperature = 35°C

Pressure = 0.37 atm

Volume of gas = ?

Solution;

Temperature = 35°C  (35+273 =308K)

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

Now we will put the values in formula.

V = nRT/P

V = 0.83 mol ×0.0821 atm.L/mol.K ×308K / 0.37 atm

V = 20.99 L/  0.37

V = 56.72 L

6 0
4 years ago
you think that plants can get the building materials they need to grow from soil wateror air? Which ones? Explain your answer
natali 33 [55]

Answer:

Yes they can because of natural sunlight and rain

Explanation:

Easy

4 0
3 years ago
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