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3 years ago

The area of a triangle is 7 square feet. The base is 3.5 feet. What is the measurement of the height of the triangle?

Mathematics

2 answers:

Travka [436]3 years ago

5 0

Answer:

The answer is 4

Step-by-step explanation:

The area for triangle is A=1/2bh, so

A=1/2bh

7=1/2X3.5h

You would multiply 1/2 and 3.5 together and get 1.75. Then you would divide 7 by 1.75 to get the height, which is 4

Sedaia [141]3 years ago

3 0

Answer:

Step-by-step explanation:

7 * 2 = 14

14 / 3.5= 4

Formula of a triangle: $\frac{1}{2} bh$

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Find the Area Of each circle.

Levart [38]

The area of the circle A and B is 86.54 inches and 124.62 mm

According to the statement

we have given that the radius of the circle A and b and we have to find the area of the given circle.

So, we know that the

The area enclosed by a circle of radius r is πr².

So, For area of the circle

For condition A :

diameter = 10.5 inches

then radius = 5.25

Area = πr²

Area = 3.14*27.56

Area = 86.54 inches

Now, For condition B :

radius = 6.3 mm

Area = πr²

Area = 3.14*39.69

Area = 124.62mm

So, The area of the circle A and B is 86.54 inches and 124.62 mm

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Veseljchak [2.6K]

Answer:

The area of the rectangle TOUR is 80.00 unit².

Step-by-step explanation:

The area of a rectangle is computed using the formula:

$Area\ of\ a\ Rectangle=length\times width$

Since the dimensions of the rectangle are not provided we can compute the dimensions using the distance formula for two points.

The distance formula using the two point is:

$distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Considering the rectangle TOUR the area formula will be:

Area of Rectangle TOUR = TO × OU

The co-ordinates of the four vertices of a triangle are:

T = (-8, 0), O = (4, 4), U = (6, -2) and R = (-6, -6)

Compute the distance between the vertices T and O as:

$TO=\sqrt{(4-(-8))^{2}+(4-0)^{2}}\\=\sqrt{12^{2}+4^{2}} \\=\sqrt{160} \\=4\sqrt{10}$

Compute the distance between the vertices O and U as:

$OU=\sqrt{(6-4)^{2}+(-2-4)^{2}}\\=\sqrt{2^{2}+6^{2}} \\=\sqrt{40} \\=2\sqrt{10}$

Compute the area of rectangle TOUR as follows:

$Area\ of\ TOUR=TO\times OU\\=4\sqrt{10}\times 2\sqrt{10}\\=80\\\approx80.00 unit^{2}$

Thus, the area of the rectangle TOUR is 80.00 unit².

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3 years ago

The shorter leg of a right triangle is 6m shorter than the longer leg. the hypotenuse is 6m longer than the longer leg. find the

Gennadij [26K]

Short leg = x-6m
Longer leg =x
Hypotenuse = x+6m

x² + (x-6)² =(x+6)²
x² + x²-12x+36 = x²+12x+36
2x²-12x+36= x² +12x+36
2x²-12x+36-36= x² +12x+36-36
2x² - 12x-12x = x²+12x-12x
2x² -24x-x² = x²-x²
x² -24x = 0
x(x-24)=0
x = 24

Short leg = 24-6m = 18
Longer leg =24
Hypotenuse = 24+6m=30

Check
a² + b² = c²
18² +24² =30²
324 +576 = 900
900=900

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3 years ago