How is a protein like a car engine? EXPLAIN.
1 answer:
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Answer:
(1) m = -5, b= 1
put b=1 (given)
=> y = -x/a + 1
-1/a is representing slope here which is given as -5
-1/a = -5 => a = 1/5
slope intercept form
y = mx +b
y = -5x + 1
standard form
5x +y = 1
(2). (1, -2), (3, 3)
m = 5/2
slope intercept form
y - 3 = 5/2*( x -3)
y = 5x/2 -9/2
standard form
5x -2y = 9
(3). (-2, 0) and (0,5)
m = 5/2
slope intercept form
y - 0 = 5/2 ( x+2)
y = 5x/2 + 5
standard form
5x -2y = -10
(4). a = 2, b = -7
slope intercept form
y = 7x/2 -7
standard form
7x -2y =14
(5). m=2,(3,-1)
slope intercept form
y +1 = 2(x -3)
y = 2x -7
standard form
2x -y = 7