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Ierofanga [76]
3 years ago
13

How much heat is released as a 5.89 kg block of aluminum cools from 462 °C to 315 °C. The specific heat capacity of aluminum is

0.900 J/(g*K)
Physics
2 answers:
Triss [41]3 years ago
7 0
<span>779000 J First determine the change in temperature 462=315 = 147 Since degrees C is the same unit size as degrees K, we can consider the change to be in Kelvin units. Now we have three measurements. 5890 grams, 147 K, and 0.900 J/(g*K). We want a result with the units J. So let's start multiplying and dividing as needed to cancel out everything else. J/(g*K) multiplied by K will cancel out the K term. 0.900 J/(g*K) * 147 K = 132.3 J/g Now multiply by 5890 g to cancel the g term. 132.3 J/g * 5890 g = 779247 J Round to 3 significant figures, giving 779000 J</span>
s2008m [1.1K]3 years ago
5 0
Mass, m = 5890g
Change in temperature, θ = Final_temperature - Initial_temperature
= 315 - 462°C
= -147°C

Specific heat capacity of aluminum, c = 0.900 J/(g*K) 
=mcθ
=5890g x 0.900 J/(g*K) x -147°C
=-779,247j

Answer would be C. 
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Answer:

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7 0
3 years ago
A firefighting crew uses a water cannon that shoots water at 25.0 m/s at a fixed angle of 53.0° above the horizontal. The fire-f
zysi [14]

Answer:

8.8 m and 52.5 m

Explanation:

The vertical component and horizontal component of water velocity leaving the hose are

v_v = vsin(\alpha) = 25sin(53^0) = 25*0.8 = 19.97 m/s

v_h = vcos(\alpha) = 25cos(53^0) = 25*0.6 = 15 m/s

Neglect air resistance, vertically speaking, gravitational acceleration g = -9.8m/s2 is the only thing that affects water motion. We can find the time t that it takes to reach the blaze 10m above ground level

s = v_vt + gt^2/2

10 = 19.97t - 9.8t^2/2

4.9t^2 - 19.97t + 10 = 0

t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

t= \frac{19.9658877511823\pm \sqrt{(-19.9658877511823)^2 - 4*(4.9)*(10)}}{2*(4.9)}

t= \frac{19.9658877511823\pm14.24}{9.8}

t = 3.49 or t = 0.58

We have 2 solutions for t, one is 0.58 when it first reach the blaze during the 1st shoot up, the other is 3.49s when it falls down

t is also the times it takes to travel across horizontally. We can use this to compute the horizontal distance between the fire-fighters and the building

s_1 = v_ht_1 = 15*0.58 = 8.8 m

s_2 = v_ht_2 = 15*3.49 = 52.5m

8 0
3 years ago
If you wanted to know how big a tiger is, which measurements would you use?
valina [46]

Answer:

meter, kilogram

Explanation:

Here we want to know how big the tiger is. This means that we want to measure its size and possibly its mass.

The size is actually a measure of the length of the tiger, and length is measured in meters.

The mass of an object, instead, is a measure of the "amount of matter" in the substance, and it is measured in kilograms.

The other options are wrong because:

- The second is the unit of time

- The candela is the unit of the luminous intensity

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- The ampere is the unit of the current

5 0
3 years ago
Hoping for funny and stupid answers
harina [27]

Answer:

ive once eaten octopus.. i dont recommend.. ANYWAY

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Explanation:

6 0
3 years ago
Read 2 more answers
if abus travelling at 20m/s is subject to steady decceleration of 5m/s².how long will it take yo come to rest.​
Likurg_2 [28]

Answer:

4 seconds

Explanation:

Given:

v₀ = 20 m/s

v = 0 m/s

a = -5 m/s²

Find: t

v = at + v₀

0 m/s = (-5 m/s²) t + 20 m/s

t = 4 s

6 0
3 years ago
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