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3 years ago

PLEASE HELP ASAPPPP!!!!!

Physics

1 answer:

Minchanka [31]3 years ago

6 0

She was actually removing energy

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Two point charges, 3.4 μC and -2.0 μC , are placed 5.0 cm apart on the x axis. Assume that the negative charge is at the origin,

Elza [17]

The electric field is zero at x = -16.45cm

Data;

q1 = 3.4 μC
q2 = -2.0 μC
distance = 5cm

<h3>The Electric Field at point 0</h3>

As the 3μC is larger than -2.0μC and the charges are opposite sign. The electric field will be zero at the negative axis.

Let the point be at x.

For an electric field to be equal to zero;

$k(\frac{q_1}{d_1})^2 + k(\frac{q_2}{d_2})^2 = 0\\\frac{3.4}{(5-x)^2} - \frac{2}{x^2} = 0\\$

Let's solve for x using mathematical methods.

$\frac{3.4x^2 - 2(5-x)^2}{(5-x)^2x^2}= 0\\ 3.4x^2 - 2(5-x^2) = 0\\3.4x^2 - 50 - 2x^2 + 20x = 0\\1.4x^2 +20x - 50 = 0$

Solving the above quadratic equation;

$x = -16.45cm$

The electric field is zero at x = -16.45cm

Learn more on electric field at a point here;

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3 years ago

Which term refers to the process by which land is worn way by natural forces or human acticity?

scZoUnD [109]

Answer:erosion

Explanation:

Erosion refers to the process by which land is worn away by natural forces or human activities

7 0

3 years ago

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A 4.0 kg block is resting on a rough horizontal table. The

Novosadov [1.4K]

Answer:

I have made a mistake in my answer

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3 years ago

It has been claimed that an insect called the froghopper (Philaenus spumarius) is the best jumper in the animal kingdom. This in

Vladimir [108]

Answer:

v=4m/s

Explanation:

The formulas for accelerated motion are:

$v=v_0+at\\x=x_0+v_0t+\frac{at^2}{2}$

We can derive the formula $v^2=v_0^2+2ad$ from them.

We have:

$v-v_0=at\\t=\frac{v-v_0}{a}$

And substitute:

$x=x_0+v_0(\frac{v-v_0}{a})+\frac{a}{2}(\frac{v-v_0}{a})^2\\x-x_0=\frac{v_0(v-v_0)}{a}+\frac{(v-v_0)^2}{2a}\\2a(x-x_0)=2v_0(v-v_0)+(v-v_0)^2=2v_0v-2v_0^2+v^2+v_0^2-2vv_0=v^2-v_0^2$

Where in the first step of the last row we just multiplied everything by 2a. Since $x-x_0$ is the displacement d, we have proved that $v^2=v_0^2+2ad$

We use then our values to calculate the final velocity when starting from rest, traveling a distance 0.002m with acceleration $4000 m/s^2$ :

$v=\sqrt{v_0^2+2ad}=\sqrt{2(4000m/s^2)(0.002m)}=4m/s$

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3 years ago

The 9 kg block is then released and accelerates

katrin [286]

Answer: 1458

explanation

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3 years ago