Answer:
- 32.823 kJ
- 190.4 kJ
- 260.00 kJ
- 180.012 kJ
Step-by-step explanation:
The conversion factor for food energy or thermochemical calorimetry* is ...
1 calorie = 4.184 J
1000 calorie = 4.184 kJ
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a. 7845 cal = 7845·4.184 J = 32,823 J = 32.823 kJ
b. 4.55·10^4 cal = 4.55·10^4·4.184 J = 1.904·10^5 J = 190.4 kJ
c. 62.142 kcal = 62.142·4.184 kJ = 260.00 kJ
d. 43,024 cal = 43,024·4.184 J = 180,012 J = 180.012 kJ
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* The thermochemical calorie is defined in terms of the heat capacity of water. An international calorie of 4.1868 J is defined in terms of energy, without respect to the heat capacity of water.
Look at the picture.
c.
1 unit right (+1); 2 units down (-2)
A(1, 3) → A'(1+1, 3-2) → A'(2, 1)
B(4, 5) → B'(4+1, 5-2) → B'(5, 3)
C(3, 1) → C'(3+1, 1-2) → C'(4, -1)
d.
(x, y) → (x + 1, y - 2)
Slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.
First, find slope using the given coordinates. Formula for slope: y₁ - y₂ / x₁ - x₂.
Our coordinates are (-2, 5) and (2, -7). Plug them in and simplify.
5 - (-7) / -2 - 2
5 + 7 / -4
12/-4
-3
The slope is -3. The equation becomes y = -3x + b.
To find b, plug an (x, y) coordinate on the line in for x and y in the equation and solve. I'll use (-2, 5)
y = -3x + b
5 = -3(-2) + b
5 = 6 + b
-1 = b
The y-intercept is (0, -1). The equation can now be completed!
<h3>
Answer:</h3>
y = -3x - 1
Answer: c= $( 5 x 5.20)
Step-by-step explanation:
Given: Total people =5
Money paid by each person = $5.20
Total cost of the sundae = (Number of people ) x (Money paid by each person)
Total cost of sunday : c= 5 x ($5.20)
i.e.Total cost of sunday = $(5 x 5.20)
i.e.Total cost of sunday = $ 26
Hence, the required equation to represent the total cost (c) of the sundae:
c= $( 5 x 5.20)
Answer:
1
Step-by-step explanation:
We are given the expression
and are asked to find the value of it.
To solve this, we can use the exponent rule of multiplying the exponent inside of the parenthesis with the one outside of the parenthesis.



Anything with an exponent of zero equals 1. Therefore :
