Answer:
450 m^2
Step-by-step explanation:
let the length be y m (the single side)
let the width be x m
so according to the question
2x + y = 60
or, y = 60 - 2x
now, Area = xy
= x(60-2x)
= -2x^2 + 60x
d(Area)/dx = -4x + 60
= 0 for a max of area
-4x + 60 = 0
x = 15
then y = 30
the width has to be 15 m, and the length has to be 30 m for a maximum area of 15(30) or 450 m^2.
<span> OK
x + x + 1 =51
2x +1 =51
2x =50
x=25
The two numbers are 25, and 26.
Hope that helps :)</span>
Given:
A rope tied from a tent pole to a stake in the ground forms 55 degrees angle with the ground.
The pole is 3 feet from the stake.
To find:
The length of the rope to the nearest tenth of a foot.
Solution:
First draw a diagram according to the given information as shown below.
We know that, in a right angled triangle,
In triangle ABC,
Therefore, the length of the rope is 5.2 foot.
Answer:26.9 feet
Step-by-step explanation:
SOH-CAH-TOA
\tan M = \frac{\text{opposite}}{\text{adjacent}}=\frac{74}{x}
tanM=
adjacent
opposite
=
x
74
\tan 70=\frac{74}{x}
tan70=
x
74
x\tan 70=74
xtan70=74
Cross multiply.
\frac{x\tan 70}{\tan 70}=\frac{74}{\tan 70}
tan70
xtan70
=
tan70
74
Divide each side by tan 70.
x=\frac{74}{\tan 70}=26.9338\approx 26.9\text{ feet}
x=
tan70
74
=26.9338≈26.9 feet
Type into calculator and roundto the nearest tenth of a foot.
L
M
N
74
26.9
(opposite of ∠M)
(adj. to ∠M)
(hypotenuse)
70°
