Question

There are 11 balls numbered 1 through 11 placed in a bucket. What is the probability of reaching into the bucket and randomly drawing three balls numbered 4, 9, and 7 without replacement, in that order? Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.

Answer 1

Answer:

Probability of drawing four balls numbered 1, 4, 8, and 6 from a 8 ball bucket = 0.041667

Step-by-step explanation:

Probability is  of the ratio of number of favorable outcomes to the total number of outcomes.

Here outcome is drawing 4 balls from a 8 ball bucket.

Favorable outcome is randomly drawing four balls numbered 1, 4, 8, and 6.

Total number of ways in which 4 balls from a 8 ball bucket can be drawn is given by 8 x 7 x 6 x 5 = 1680.

Total number of ways in which drawing four balls numbered 1, 4, 8, and 6 from a 8 ball bucket is given by 8C₄

   

Probability of drawing four balls numbered 1, 4, 8, and 6 from a 8 ball bucket is given by

      

Probability of drawing four balls numbered 1, 4, 8, and 6 from a 8 ball bucket = 0.041667

Read more on Brainly.com - brainly.com/question/13409547#readmore