Dilation about the origin multiplies every coordinate by the scale factor.
C' = 4(-5, 2) = (-20, 8)
A' = 4(-4, 4) = (-16, 16)
T' = 4(-1, 2) = (-4, 8)
We have that
<span>y = -x</span>²<span>+8x
we know that
when the ball hint the ground is the x-intercepts of the graph
the x-intercepts is for y=0
so
0=-x</span>²+8x--------> x²-8x=0----> x*(x-8)=0
the solution is
x=0
x=8
the x intercepts are the points (0,0) and (8,0)
the distance between the x intercepts points =[8-0]-----> 8 ft
the answer is
8 ft
see the attached figure
(x - h)^2 + (y - k)^2 = r^2
x^2 + (y + 6)^2 = 100
we can rewrite this as
(x-0)^2 + (y - -6)^2 = 10^2
the center is (0,-6) and the radius is 10
No such thing as cot (61,4). I think you meant to say cot (61.4°). See the difference?
So, cot (61.4°) is approximately -0.139844.
Rounded to 3 decimal places we get -0.140.