<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2>
<h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2>
<h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2>
<h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>
Answer:
105 feet.
Step-by-step explanation:
The longer diagonal is opposite the longer angle in the parallelogram.
The longer angle = 180 - 36 = 144 degrees. (Reason: he same side angles are supplementary).
So, by the law of cosines:
x^ 2 = 40^2 + 70^2 - 2*40*70 cos 140 where x = the diagonal.
x^2 = 11030.50
x = 105.03 feet.
No solution to this problem