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Genrish500 [490]
2 years ago
7

A fence post is 12 feet tall. A chain is attached to the top of the fence post and fastened to the ground 9 feet from the base o

f the fence post. What is the length of the chain?
Mathematics
2 answers:
nirvana33 [79]2 years ago
8 0

Answer:

15 feet

Step-by-step explanation:

Use the Pythagorean theorem which is a^2 + b^2 = c^2

a and b represents the legs of the triangle

c represents the hypotenuse (which is the chain)

Natasha2012 [34]2 years ago
7 0

Answer: 15ft chain length

Step-by-step explanation: A right triangle is formed from the picture. Using pythagorean theoreom

12^2+9^2=c^2

225=c^2

15=c

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Hellp me solve this thanks
stellarik [79]

Answer:

c. 10 cm

Step-by-step explanation:

The parallel sides of trapizium are the bases so

base 1(B1) =9cm , base(B2)= 12cm

area(a) = 105 {cm}^{2}

the perpendicular distance means the height so lets find the height

area of trapizium= <u>B1 + B2</u> × h

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2

{105cm}^{2}(the \: given \: area)  =  \frac{9cm(the \: given \: base) + 12cm(the \: given \: base)}{2}  \times h

{105cm}^{2}  =  \frac{21cm}{2}  \times h

now we crisscross

{105cm}^{2} \times 2 = 21cm \times h

{210cm}^{2}  = 21cm \times h

\frac{ {210cm}^{2} }{21cm}  =  \frac{21cm \: }{21cm}  \times h

h = 10 cm

hope u like it ‍❤️‍‍❤️‍‍❤️‍

For any question comment me

4 0
3 years ago
Evaluate ( 4 upon 3 ) -2<br><br><br>please amswer fast​
Taya2010 [7]
<h2><u>Solution</u></h2>

\frac{4}{3}  - 2 \\  \\   = \frac{4 - 6}{ 3}  \\  \\  =  \frac{ - 2}{3}

<h3>Hope This Helps You ❤️</h3>
6 0
3 years ago
For the region bounded by y=2x​, the​ x-axis, and x=1​, determine which of the following is​ greater: the volume of the solid ge
telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

\int\limits^1_0 {(pi)y^{2} } \, dx

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

7 0
3 years ago
Is the following statement always, sometimes, or never true? “The supplement of an acute angle is an obtuse angle.” Explain your
balu736 [363]

Answer:

Always

Step-by-step explanation:

An acute angle is an angle that is less than 90. Supplementary angles add up to 180.

So 180-89= 91

An obtuse angle is any angle that is greater than 90.

Here's a link to a better explanation.

brainly.com/question/14180317

7 0
3 years ago
Read 2 more answers
Can someone please help me ASAP​
deff fn [24]

Answer:

QR = 17 cm

Step-by-step explanation:

Δ RST is a 5- 12- 13 triangle with hypotenuse RT = 13 cm , then

TS = 5 cm and PT = 2 × 5 = 10 cm

So PS = 10 + 5 = 15 cm

PS is parallel to the vertical line from vertex Q and intersects the horizontal line projected from SR of length 20 - 12 = 8 cm

Using the right triangle formed calculate QR using Pythagoras' identity

QR² = 15² + 8² = 225 + 64 = 289 ( take square root of both sides )

QR = \sqrt{289} = 17

3 0
3 years ago
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