Answer:
c. 10 cm
Step-by-step explanation:
The parallel sides of trapizium are the bases so
base 1(B1) =9cm , base(B2)= 12cm

the perpendicular distance means the height so lets find the height
area of trapizium= <u>B1 + B2</u> × h
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2


now we crisscross



h = 10 cm
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<h2><u>Solution</u></h2>

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Answer:
The correct answer B) The volumes are equal.
Step-by-step explanation:
The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

which when evaluated gives 4pi/3.
Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.
Answer:
Always
Step-by-step explanation:
An acute angle is an angle that is less than 90. Supplementary angles add up to 180.
So 180-89= 91
An obtuse angle is any angle that is greater than 90.
Here's a link to a better explanation.
brainly.com/question/14180317
Answer:
QR = 17 cm
Step-by-step explanation:
Δ RST is a 5- 12- 13 triangle with hypotenuse RT = 13 cm , then
TS = 5 cm and PT = 2 × 5 = 10 cm
So PS = 10 + 5 = 15 cm
PS is parallel to the vertical line from vertex Q and intersects the horizontal line projected from SR of length 20 - 12 = 8 cm
Using the right triangle formed calculate QR using Pythagoras' identity
QR² = 15² + 8² = 225 + 64 = 289 ( take square root of both sides )
QR =
= 17