Answer:
(d)
Step-by-step explanation:
Given

Required
The intercepts
The x intercepts are where the graph crosses x axis.
From the attached plot, they are:
and 
These represent the start and end of the ball that is launched.
Hence, (d) is true
Answer:
option A, C and D
Step-by-step explanation:
Each relation is a function if each input has only one output
{a, 1), (6, 1), (C, 1)
This relation is a function because each input has only one output
{a, a),(a, b),(a, c)}
This relation is not a function because input 'a' has only three output
{(1, a), (2, a),(3, a)}
This relation is a function because each input has only one output
{a, a), (b, b), (C, c)}
This relation is a function because each input has only one output
put the equation 2x - y = 16 in the form of y = mx + c
2x - y = 16
2x = 16 + y
y = 2x - 16
the slope of this line is 2. the slope of a line perpendicular to it would be the negative reciprocal of 2. in other words, it would multiply with 2 to give -1.
you can form this equation with that info
2x = -1
x = -1/2
OR
you can flip and change the sign (numerator) of 2/1
2/1
= -1/2
Answer:
4.428 hours
Step-by-step explanation:
If the learning rate is 0.81, the slope of the learning curve is:

The time it takes to produce the n-th unit is:

If T1 = 8 hours, the time required to produce the seventh unit will be:

It will take roughly 4.428 hours.
Let x represent amount invested in the higher-yielding account.
We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be
.
We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.
, where,
I = Amount of interest,
P = Principal amount,
r = Annual interest rate in decimal form,
t = Time in years.
We are told that interest rates are 6% and 10%.


Amount of interest earned from lower-yielding account:
.
Amount of interest earned from higher-yielding account:
.

Let us solve for x.



Therefore, the man invested $30,000 at 10%.
Amount invested in the lower-yielding account would be
.
Therefore, the man invested $60,000 at 6%.