Just multiply 20 by how many days there are in a month.
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Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
-0.5
Step-by-step explanation:
- slope=rise/run or y/x in other words(y2-y1/x2-x1)
- (y2-y1) is 3-2 so y2-y1=1
- (x2-x1) is 3-5 so x2-x1= -2
- -1/2 or -0.5 would be the slope.
Answer:
Part A:y=4,1,0,1,4
Step-by-step explanation:
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