The balanced redox reaction, if it occurs in acidic solution, is
5C₂O₄²⁻(aq) + 2MnO₄⁻(aq) + 16H⁺-----> 10CO₂(g) + 2Mn²⁺(aq) + 8H₂O(l)
<h3>What are redox reaction?</h3>
Redox reactions are those in which loss and again of electrons occur.
To balance the redox reaction, we must first break the whole reaction into half equations;
Oxidation half equation
Reduction half equation
Now combine both the reactions
Thus, the coefficient of H₂C₂O₄ is 5 and that of water is 8.
Learn more about redox reactions
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Answer:
0.21 M
Explanation:
Molarity is the calculation of the solution in which the number of solute per liter of the solutions. It is the most common measurement unit that is used to measure the concentration of the solution.
The molarity is the unit that is used to measure or calculate the volume of the solvent. The amount of solvent is used in the chemical reaction.
The amount of the two solvent in the same quantity is measured by the formula called c1v1 and c2v2.
____NaNO3 + ___PbO --> ___Pb(NO3)2 + ___Na[2]O
To balace the eqaution, you need to have the same number of atoms for each element on both the reactant (left) and product (right) side.
To start off, you wanna know the number of atoms in each element on both sides, so take it apart:
[reactants] [product]
Na- 1 Na- 2
N- 1 N- 2(it's 2 because the the subscript [2] is outside of the parenthesis)
O- 4 O- 7 (same reason as above)
Pb- 1 Pb- 1
Na is not balanced out, so add a coefficient to make it the same on both sides.In this case, multiply by 2:
2NaNO3
Now Na is balanced, but the N and O are also effected by this, so they also have to be multiplied by 2 and they become:
Na- 2 Na- 2
N- 2 N- 2 (it balanced out)
O- 7 (coefficient times subscript, plus lone O) O- 7 (balanced out)
Pb was already balanced so no need to mess with it, just put a 1 where needed (it doesn't change anything).
Now to put it back together, it will look like this:
2NaNO3 + 1PbO --> 1Pb(NO3)2 + 1Na[2]O
The largest transition metal is copernicium with 112 protons
Answer:
704.6 g CO2
Explanation:
MM sucrose = 342.3 g/mol
MM CO2 = 44.01 g/mol
g CO2 = 456.7 g sucrose x (1 mol sucrose/MM sucrose) x (12 moles CO2/1 mol sucrose) x (MM CO2/1mol CO2) = 704.6 g CO2
