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BabaBlast [244]
2 years ago
5

The nucleus of an atom is dense and positively charged. What was observed when positively charged particles were radiated onto a

gold atom during Rutherford's experiment because of this?
Negative charges were concentrated at the center of the atom.
Particles that struck the center of the atom were repelled.
Particles that struck the edges of the atom were repelled.
Positive charges were distributed all over the atom.
Chemistry
2 answers:
ankoles [38]2 years ago
8 0
<span>According to my knowledge, I feel the answer is -
Particles that struck the center of the atom were repelled.

Hope this helps!
</span>
romanna [79]2 years ago
7 0

<u>Answer:</u> The correct answer is particles that struck the center of the atom were repelled.

<u>Explanation:</u>

Rutherford gave an experiment which is known as gold foil experiment.

In his experiment, he took a gold foil and bombarded it with the alpha particles (carrying positive charge). These alpha particles are also known as  helium nucleus. It is represented as _2^4\alpha.

He thought that these particles will pass straight through the foil, but to his surprise, some of them deflected their path and a few of them bounced back.

From this he concluded that in an atom, a small positive charge in the center is present. Due to this positive charge, the alpha particles deflected their path and some of them bounced straight back from their path.

Hence, the correct answer is particles that struck the center of the atom were repelled.

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A chemist adds 1.80L of a 1.1/molL aluminum chloride AlCl3 solution to a reaction flask. Calculate the millimoles of aluminum ch
amm1812

Answer:

2000 millimoles of AlCl₃

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 1.8 L

Molarity of solution = 1.1 mol /L

Millmole of AlCl₃ =?

Next, we shall determine the number of mole of AlCl₃ in the solution.

This can be obtained as follow:

Volume of solution = 1.8 L

Molarity of AlCl₃ solution = 1.1 mol /L

Number of mole of AlCl₃ =?

Molarity = mole /Volume

1.1 = Number of mole of AlCl₃ / 1.8

Cross multiply

Number of mole of AlCl₃ = 1.1 × 1.8

Number of mole of AlCl₃ = 1.98 moles

Finally, we shall convert 1.98 moles to millimoles. This can be obtained as follow:

1 mole = 1000 millimoles

Therefore,

1.98 mole = 1.98 mole × 1000 millimoles / 1 mole

1.98 mole = 1980 millimoles

1.98 mole ≈ 2000 millimoles

Thus, the chemist added 2000 millimoles of AlCl₃

7 0
2 years ago
1 points)<br> You have 300 grams of Al2(CO3)3. How many moles are produced?
Pavlova-9 [17]

Answer:

0.5133805136 moles.

Explanation:

1 gram of Al2(Co3)3 equals 0.0017112683785004 moles, we need the amount of moles produced in 300 grams of Al2(CO3)3, so we have to multiply 1 gram of Al2(CO3)3 times 300: 0.0017112683785004 x 300, in conclusion,

300 grams of Al2(Co3)3 equals 0.5133805136.

5 0
2 years ago
A charasteristic that helps a living thing survive
Fantom [35]
Ability to adapt to their environment?? there isn't much context to the question /:
3 0
3 years ago
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Although not usually soluble in plain water, an amphoteric oxide or hydroxide is: 1. soluble in neutral solutions. 2. soluble in
Aleksandr [31]

Answer:

The correct option is: 4. soluble in both acidic and basic solutions

Explanation:

Oxide is a chemical compound formed by an element with oxygen. In such compounds, the oxygen is generally present in the -2 oxidation state.

Whereas, hydroxide is a chemical compound formed by an element with hydroxyl group (-OH).

<em>Oxides and hydroxides of some elements are </em><em>amphoteric</em><em> in nature.</em> <u><em>Such compounds can behave as an acid in basic medium and behave as a base in acidic medium.</em></u>

<u>Therefore, amphoteric oxides and hydroxides are soluble in both acidic and basic solutions.</u>

5 0
3 years ago
Plz answer very easy question
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A: they all have protons
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c:protons neutrons and electrons
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7 0
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