AgNO3(aq) + KCl (aq)-----> AgCl(s) + KNO3(aq)
Ag ^+(aq) + NO3^-(aq) + K^+ (aq) + cl^- (aq) ----> AgCl(s) + K^+(aq) + NO3^-(aq)
net ionic equation
Ag ^+(aq) + Cl^-(aq) ----> AgCl(s)
Answer:
The response can be defined as follows:
Explanation:
ATP is a hydrolysis energy-saving money of the cell. It is used to support the cell's endothermic processes.
![ATP\ +\ H_{2}O\ \rightleftharpoons \ ADP\ +\ P_{i}\\\\Q\ = \ \frac{[ADP][P_{i}]}{[ATP][H_{2}O]}\\\\ADP= 0.250 \ M\\\\P_i = 0.010 \ M\\\\ATP = 0.150 \ M\\\\H_2O = 55.55 \ M\\\\\Delta G \ =\ \Delta G^{o}\ +\ 2.303\ RT\ \log\ Q\\\\R = 8.314 \frac{J}{mol\ K}\\\\T = 298\ K\\\\](https://tex.z-dn.net/?f=ATP%5C%20%2B%5C%20H_%7B2%7DO%5C%20%5Crightleftharpoons%20%5C%20ADP%5C%20%2B%5C%20P_%7Bi%7D%5C%5C%5C%5CQ%5C%20%3D%20%5C%20%5Cfrac%7B%5BADP%5D%5BP_%7Bi%7D%5D%7D%7B%5BATP%5D%5BH_%7B2%7DO%5D%7D%5C%5C%5C%5CADP%3D%200.250%20%5C%20M%5C%5C%5C%5CP_i%20%3D%200.010%20%5C%20M%5C%5C%5C%5CATP%20%3D%200.150%20%5C%20M%5C%5C%5C%5CH_2O%20%3D%2055.55%20%5C%20M%5C%5C%5C%5C%5CDelta%20G%20%5C%20%3D%5C%20%5CDelta%20G%5E%7Bo%7D%5C%20%2B%5C%202.303%5C%20RT%5C%20%5Clog%5C%20Q%5C%5C%5C%5CR%20%3D%208.314%20%5Cfrac%7BJ%7D%7Bmol%5C%20K%7D%5C%5C%5C%5CT%20%3D%20298%5C%20%20K%5C%5C%5C%5C)
Answer: 160 ml
Explanation:
The expression used will be :
where,
= concentration of Ist alcohol solution= 10%
= concentration of 2nd alcohol solution= 55%
= volume of Ist alcohol solution = 200 ml
= volume of 2nd alcohol solution= v ml
= concentration of resulting alcohol solution= 30%
= volume of resulting alcohol solution= (v+200) ml
Now put all the given values in the above law, we get the volume of added.
By solving the terms, we get :
Therefore, the volume of 55% mixture needed to be added to obtain the desired solution is 160 ml.
Ba (OH) 2 Ba(OH) 2 is a string electrolyte, determine the concentration of each of the individual in a 0.400m Ba (OH)20.400m