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konstantin123 [22]
3 years ago
8

How many moles is 8.72x10^24 atoms? can you solve the equation too?

Chemistry
1 answer:
vampirchik [111]3 years ago
4 0

Answer:

<h2>14.49 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.72 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  =  14.48504...

We have the final answer as

<h3>14.49 moles</h3>

Hope this helps you

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What happened to the sound as vibration of an object increase in strength​
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Answer:

A.The sound becomes louder.

And

C.The sound waves get further.

Explanation:

Louder the sound it will travel long.

5 0
2 years ago
Which of he following compounds is always part of an aqueous solution
weqwewe [10]

Answer: Water because if we say aqueous it means it resembles water or related to water.

7 0
3 years ago
Valeric acid, HC5H9O2 (Ka = 1.5 ✕ 10−5), is used in the manufacture of magnesium valerate, a nerve-calming agent. What is the hy
Studentka2010 [4]

Answer:

[H^+]=0.00332M

Explanation:

Hello,

In this case, considering the dissociation of valeric acid as:

HC_5H_9O_2 \rightleftharpoons C_5H_9O_2 ^-+H^+

Its corresponding law of mass action is:

Ka=\frac{[H^+][C_5H_9O_2^-]}{[HC_5H_9O_2]}

Now, by means of the change x due to dissociation, it becomes:

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x=0.00332M

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[H^+]=x=0.00332M

Best regards.

7 0
3 years ago
3.79 x 10^8<br> =<br> .mol<br> 2<br> 2<br> kg.m<br> g.cm
yuradex [85]

Answer:

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3 0
3 years ago
NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution that is 0.084 M in
kolbaska11 [484]
Answer is: pH of solution is 5,17.
Kb(NH₃) = 1,8·10⁻⁵.
c(NH₄Cl) = 0,084 M = 0,084 mol/L.
Chemical reaction: NH₄⁺ + H₂O → NH₃ + H₃O⁺.
Ka · Kb = 10⁻¹⁴.
Ka(NH₄⁺) = 10⁻¹⁴ ÷ 1,8·10⁻⁵.
Ka(NH₄⁺) = 5,55·10⁻¹⁰.
[H₃O⁺] = [NH₃]  = x.
Ka(NH₄⁺) = [H₃O⁺] · [NH₃] ÷ [NH₄⁺].
5,55·10⁻¹⁰ = x² ÷ (0,084 M - x).
Solve quadratic equation: x = [H₃O⁺] = 6,8·10⁻⁶ M.
pH = -log[H₃O⁺].
pH = -log(6,8·10⁻⁶ M) = 5,17.
7 0
3 years ago
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