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Andreas93 [3]
3 years ago
15

Jeremiah flies an airplane for 2.7 hours at an average speed of 304.6 miles per hour. How far did Jeremiah fly?

Mathematics
1 answer:
Nostrana [21]3 years ago
8 0
822.42 miles in 2.7 hours

304.6 × 2.7 = 822.42
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a die and a coin is rolled and tossed respectively.what is the probability of getting a five and a tail ?​
GrogVix [38]

Answer:

1/12

THIS DESERVES BRAINLISTTT

Step-by-step explanation:

There are 12 possible outcomes, 6 for the die for each of the 2 for the coin. Only one comprises a 5 and a tail so the probability, assuming a fair coin and die, is 1/12.

8 0
2 years ago
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Which of the lines graphed has a slope of 3 and a y-intercept of 2?​
marshall27 [118]

Answer:

Step-by-step explanation:

I can't really see the graphs very well but it is either A or B.

If you want to find your answer, see which line starts at 2 on. the y line. From there using your finger go up 3 and right 1

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Plzzz help thank you very much!!
olasank [31]

80.

The opposite side of the arc is equal to its opposite.

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3 years ago
Find the 30th term of the following sequence. 1, 7, 13, 19, ...
postnew [5]

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175

Step-by-step explanation:

a30 = a1 + f × (n-1)

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8 0
3 years ago
According to the National Institute on Drug Abuse, a U.S. government agency, 17.3% of 8th graders in 2010 had used marijuana at
miskamm [114]

Answer:

The conditions for use of the normal model to represent the distribution of sample proportion are not met. He should increase the sample size until the conditions are met.

If the test is done anyway, the null hypothesis failed to be rejected.

The conclusion is taht there is not enough evidence to support the claim that the percentage is lower in this district.

Step-by-step explanation:

The conditions for use of the normal model to represent the distribution of sample proportion are not met, as the affirmative responses are less than 10.

np=80*0.1=8

If the test of hypothesis is done as if the conditiones were met, we know that the claim is that  the percentage is lower in this district.

Then, the null and alternative hypothesis are:

H_0: \pi=0.173\\\\H_a:\pi

The significance level is 0.05.

The sample has a size n=80.

The sample proportion is p=0.1.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.173*0.827}{80}}\\\\\\ \sigma_p=\sqrt{0.001788}=0.042

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.1-0.173+0.5/80}{0.042}=\dfrac{-0.067}{0.042}=-1.578

This test is a left-tailed test, so the P-value for this test is calculated as:

P-value=P(z

As the P-value (0.057) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that  the percentage is lower in this district.

7 0
3 years ago
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