Answer:
36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Find the probability that her pulse rate is between 69 beats per minute and 81 beats per minute.
This is the pvalue of Z when X = 81 subtracted by the pvalue of Z when X = 69.
X = 81



has a pvalue of 0.6844
X = 69



has a pvalue of 0.3156
0.6844 - 0.3156 = 0.3688
36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.
Answer:
The Equation which shows the equality is 53 = 2 h + 5 ,
The age of Sunny's house is 24 years old
Step-by-step explanation:
Given as ;
The age of the house of Chen's is 53 years old
Let the age of of the house of sunny = h years old
So, according to question
Chen's house age is 5 years more than twice the age of sunny's house
I.e Chen's house age = 2 × sunny's house age + 5
Or, 53 = 2 × h + 5
or, 2 × h = 53 - 5
so . 2 × h = 48
∴ h =
= 24 years
Hence The Equation which shows the equality is 53 = 2 h + 5 , And The age of Sunny's house is 24 years old . Answer
Answer:
35/8
Step-by-step explanation:
4×8= 32 plus the 3/8 equals 35/8
hope it helps
Answer:
50 is the old value and 23 is the new value. In this case we have a negative change (decrease) of -54 percent because the new value is smaller than the old value. Using this tool you can find the percent decrease for any value.
Answer:
The answer is X. because it follows along the line most perfectly.