A: x (isabella)
3x+x=36
b: 3x+x=36
4x=36
x=9
3x=27
c: Joseph is 27 years old.
Answer:
15 nuts do not get found.
Step-by-step explanation:
Given that Of a squirrel's hidden nuts, for every 5 that get found, there are 3 that do not get found.
Total number of nuts squirrel had hidden = 40
Proportion of nuts not found to total = 3/(3+5) = 3/8
Hence out of 40, nuts not found =3/8(40) = 15 nuts.
15 nuts would not be found and 25 nuts would be found if squirrel had hidden in total 40 nuts.
This is because the proportion of found:unfound = 5:3
Hence 25:!5 =5:3 satisfies this
15 nuts are not found.
1.y-4.90 = 2.4(x-1) 2. 24x-10y= -25
Step-by-step explanation:
The point-slope form of an equation is written as ;
y-y₁ = m(x-x₁) where the focus is on the slope of the line and a point on the line.
In this case, y-4.90 = 2.4(x-1)
The standard form an equation is written as :
Ax+By=C ,where x and y are variables and A,B and C are integers.
In this case; 24x-10y= -25
Learn More
Point-slope intercept form of an equation; brainly.com/question/11016508
Keywords :point-slope, standard form, equation
#LearnwithBrainly
Answer:
Part A: impossible
Part B: Either equal or blue
Part C: 9 green and 2 blue were added
Step-by-step explanation:
Part A:
The only colors included in this problem are red, blue, and green. There is no black colored pencil, therefore, it is impossible to get one from the box.
Part B:
I'm not sure what you're asking in this question, but I will give you the two choices. If it is before the additional 11 colored pencils are added to the box, the chance of drawing a red and the chance of drawing a blue will be equal, because both of them have 11 of each color. If it is after the additional 11 colored pencils are added to the box, then the chance of drawing a blue colored pencil will be greater than the chance of drawing a red colored pencil. After the 11 colored pencils are added, there are 13 blue and 11 red. The blue is greater.
Part C:
The least number of green colored pencils added has to be 9, because the chance of drawing a green pencil is now greater than the chance of drawing a red pencil. If we add 8 more green pencils, the likelihood would be the same. Therefore, the number of green colored pencils added has to be at least 9. If we have the last 2 colored pencils be blue, then there would be 11 red, 13 blue, and 12 green. This fits all the conditions, therefore, adding 9 green colored pencils and 2 blue colored pencils is the answer.
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