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rjkz [21]
3 years ago
13

Mark is taking pledges for bike-a-thon fundraiser. John pledged $2.00, plus $1.75 for each mile Mark bikes. Kiara pledged $5.25,

plus $0.25 for each mile Mark bikes. Write an expression for the numbers of dollars pledged and the number of dollars kiara pledged . Use M for the number of miles that Mark bikes.
Mathematics
1 answer:
Shkiper50 [21]3 years ago
4 0

Answer:

The equation for the amount of dollars pledged in total is f(M) = 2.00M + 7.25, and the amount for just Kiara is f(M) = 0.25M + 5.25

Step-by-step explanation:

The amount they pledge up front is a constant and therefore need to be added to the end of the equation. The amount per mile should be a variable amount. This gets multiplied by the M variable. So we start with the Kiara amount.

0.25 per mile = 0.25M

5.25 pledged = 5.25

Now put them together to get f(M) = 0.25M + 5.25

Do the same with Mark.

1.75 per mile = 1.75M

2.00 pledged = 2.00

Now put them together to get f(M) = 1.75M + 2.00

To get the final total, we add both equations together.

f(M) =  0.25M + 5.25 + 1.75M + 2.00

f(M) = 2.00M + 7.25

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B. 25/20 using gcf simplified is 5/4
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According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e
slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that p = 0.09

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

So

P(X < 4) + P(X \geq 4) = 1

We want P(X \geq 4)

So

P(X \geq 4) = 1 - P(X < 4)

In which

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.09)^{0}.(0.91)^{12} = 0.3225

P(X = 1) = C_{12,1}.(0.09)^{1}.(0.91)^{11} = 0.3827

P(X = 2) = C_{12,2}.(0.09)^{2}.(0.91)^{10} = 0.2082

P(X = 3) = C_{12,3}.(0.09)^{3}.(0.91)^{9} = 0.0686

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3225 + 0.3827 + 0.2082 + 0.0686 = 0.982

Finally

P(X \geq 4) = 1 - P(X < 4) = 1 - 0.982 = 0.0180

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

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Answer:

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CD=5 cm 6 mm  -----> convert to cm -----> CD=5+6/10=5.6 cm

DE=35 mm ------> convert to cm -----> DE=35/10=3.5 cm

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