2 years ago

What is the slope of f(x)=x^2+3 when x=-1 ?

Mathematics

1 answer:

irinina [24]2 years ago

8 0

F(x)=(-1)^2+3
f(x)=1+3
f(x)=4

The slope is 0 because 4 is a constant.

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What is the solution of the system?

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Greetings!

Solve the System, using Elimination:
$\left \{ {{4x+2y=18} \atop {2x+3y=15}} \right.$

Multiply Equation #2 by 2:
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Eliminate variable x:
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$4y=-12$

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Input this value into one of the Equations:
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$4x+2(3)=18$

Simplify:
$4x+6=18$

$(4x+6)+(-6)=(18)+(-6)$

$4x=12$

Divide both sides by 4.
$\frac{4x}{4}= \frac{12}{4}$

$x=3$

The Solution to this System (The Point of Intersection):
$\boxed{(3,3)}$

I hope this helped!
-Benjamin

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