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PilotLPTM [1.2K]

3 years ago

8

Use the graph of f(x) to find the solution to the equation f(x)=0

1 answer:

myrzilka [38]3 years ago

7 0

The solution will be where the graph crosses the x-axis.

When a graph crosses the x-axis, the value of the function is 0. Just look at your graph and look at the x-values where the graph crosses the x-axis.

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An electrical power company is looking to expand into a new market. Before they commit to supplying the new area with electricit

TiliK225 [7]

Answer:

atleast 385

Step-by-step explanation:

Given that an electrical power company is looking to expand into a new market. Before they commit to supplying the new area with electricity, they would like know the mean daily power usage for homes there.

Population std deviation = $\sigma = 50$

Sample size = $n$

STd error of sample mean = $\frac{50}{\sqrt{n} }$

Margin of error for 95% would be Critical value ( std error)

Here since population std dev is known we can use Z critical value= 1.96

$1.96*\frac{50}{\sqrt{n} }19.6^2\\n>384.16$

Sample size should be atleast 385

5 0

3 years ago

Four times a number<br> decreased by ten is 34.<br> Write an equation & solve.

igomit [66]

4x - 10 = 34
4x +10 +10
4x = 44
4x/4 = 44/4
x = 11

5 0

3 years ago

Casey bought a 15.4 pound turkey and an 11.6 pound ham for Thanksgiving and paid $38.51.

White raven [17]

Answer:

h = 1.74

t = 1.19

Step-by-step explanation:

15.4t + 11.6h = 38.51

10.2t + 7.3h = 24.84

15.4•t + 11.6•h = 38.51

10.2•t + 7.3•h = 24.84

11.6h+15.4t = 38.51

7.3h+10.2t = 24.84

h = 87

50

= 1.74

t = 119

100

= 1.19

6 0

2 years ago

Find the area of quadrilateral ABCD. A. 27.28 units² B. 33.08 units² C. 28.53 units² D. 26.47 units²

Ludmilka [50]

Answer:

<h3> $\boxed{ \boxed{ \bold{ \purple{ \sf{28.53 \: {units}^{2} }}}}}$ </h3>

Option C is the correct option.

Step-by-step explanation:

For ABD

$\sf{ = \frac{2.89 + 8.59 + 8.6}{2} }$

$\sf{ = \frac{20.08}{2} }$

$\sf{ = 10.04}$

∆ ABD = $\sf{ = \sqrt{10.04(10.04 - 2.89)(10.04 - 8.59)(10.04 - 8.6)} }$

$\sf{ = \sqrt{10.04 \times 7.15 \times 1.45 \times 1.44 }}$

$\sf{ = \sqrt{149.8891} }$

$\sf{ = 12.2429}$

For ∆ ACD ,

$\sf{s = \frac{8.6 + 4.3 + 7.58}{2} }$

$\sf{ = \frac{20.48}{2} }$

$\sf{ = 10.24}$

∆ ACD = $\sf{ = \sqrt{10.24(10.24 - 8.6)(10.24 - 4.3)(10.24 - 7.58} }$

$\sf{ \sqrt{10.24 \times 1.64 \times 5.94 \times 2.66} }$

$\sf{ = \sqrt{265.3456} }$

$\sf{ = 16.2894}$

Area of quadrilateral ABCD = $\sf{12.2429 + 16.2894}$

$\sf{ = 28.5323}$

$\sf{ = 28.53}$ units ²

Hope I helped!

Best regards!

8 0

3 years ago

Help meee if answer correctly I will follow you and make you brilliant

Ratling [72]

Answer:

a = 2; b = -1; and c = 3

Step-by-step explanation:

Please see attached image for the step by step answer

4 0

2 years ago