Find the solution of the inequality -3n

Determine whether the three points are collinear:

Hunter-Best [27]

Answer:

Yes

Step-by-step explanation:

Both group of points are plotted and attached below.

Red line contains the first group (29) and blue line contains the second group (30).

Both show the collinear points. The answer is yes to both.

3 0

2 years ago

A sign company charges $28 per yard for each custom made banner. Ms. Gill orders two banners that are each 1 7/8 yards yards lon

Svetlanka [38]

Answer:

$896

Step-by-step explanation:

We are given that

Charge of 1 yard for each custom-made banner=$28

Length of 1 piece=15 yards

Length of another piece=2 yards

We have to find that how much money payed by Ms.Gill for all three banners.

According to question

Cost of 15 yards long banner=$420

Cost of 2 piece of 15 yards long banner==$840

Cost of 2 yards long banner==$56

Total cost of 3 piece of banners=840+56=$896

Hence, Ms gill pay for all three banners=$896

Your Welcome;)

8 0

2 years ago

If dab=125 what is the measure of cba justify your reasoning

KonstantinChe [14]

The answer is <span>D. x=y-z-9/7</span>

8 0

3 years ago

The following prices, in dollars, of 7.5-cubic-foot refrigerators were recorded from a random sample. 314 305 344 283 285 310 3

Mariana [72]

Answer:

$t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109$

The degrees of freedom are given by:

$df=n-1=10-1=9$

And the p value would be given by:

$p_v =P(t_{9}>1.109)=0.148$

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

Step-by-step explanation:

Information given

314 305 344 283 285 310 383 285 300 300

We can calculate the sample mean and deviation with the following formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}$

$\bar X=310.9$ represent the sample mean

$s=31.09$ represent the standard deviation for the sample

$n=10$ sample size

$\mu_o =300$ represent the value to test

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to verify if the true mean is greater than 300, the system of hypothesis would be:

Null hypothesis: $\mu \leq 300$

Alternative hypothesis: $\mu > 300$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109$

The degrees of freedom are given by:

$df=n-1=10-1=9$

And the p value would be given by:

$p_v =P(t_{9}>1.109)=0.148$

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

6 0

2 years ago

What value of h makes the statement true? (17+h)+(–9) = 17+(5+(–9))

aalyn [17]

I know this is late and you probably got the answer but just in case its C. 5. :P

5 0

2 years ago

Find the solution of the inequality -3n < 81