Answer:
So we have a triangle and a semicircle.
If the triangle is equilateral, this is:
AB = BC = 6cm
Then the area of the triangle is equal to (base*height)/2
in this case:
A = (6*6)/2 = 36/2 = 18cm^2.
And the diameter of the semicircle is equal to 6cm, then the diameter is 3cm
And if the area of a circle is A = pi*r^2
then the area of half a circle is:
A = (pi/2*)3^2 = pi*4.5cm^2
Then, the area of the triangle plus the area of the semicircle is:
Total area = 18cm^2 + pi*4.5^2
Add
3
w
3
w
and
2
w
2
w
.
5
w
−
6
=
−
2
+
w
5
w
-
6
=
-
2
+
w
Move all terms containing
w
w
to the left side of the equation.
Tap for more steps...
4
w
−
6
=
−
2
4
w
-
6
=
-
2
Move all terms not containing
w
w
to the right side of the equation.
Tap for more steps...
4
w
=
4
4
w
=
4
Divide each term by
4
4
and simplify.
Tap for more steps...
w
=
1
Answer:
Where's the x?
I am assuming that the problem must be
-3 + 42 > 3x
if that is true, then
<u>x < 13</u>.
As this statement is, -3 + 42 > 3 is a true statement because -3 + 42 = 39, and
39 > 3 [39 is always greater than 3]
Step-by-step explanation:
Let me know if you need a step by step.
Answer:
1 hour
Step-by-step explanation:
I find these easiest to work by considering the initial difference in distance and the speed at with that gap is closing.
__
The gap is 15 miles, the distance the first ship is from harbor when the second ship starts.
The rate of closure is the difference in the speeds of the two ships:
60 mph -45 mph = 15 mph
Then the closure time is ...
time = distance/speed
time = (15 mi)/(15 mi/h) = 1 h
It will take the second ship 1 hour to catch up to the first ship.
