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Shkiper50 [21]
4 years ago
8

Help please with angles

Mathematics
1 answer:
Diano4ka-milaya [45]4 years ago
4 0
I think angle 8 because if you look at the angle 1 it is equivalent to angle 8 in length just in different positions
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Can anyone help me with this problem
antiseptic1488 [7]
Sure, fill in x as the numbers on the table, and the correct answer is A
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Ubehebe crater in Death Valley has a diameter of a little more than 1/2 mile. If latisha walks around it's rim at a rate of 2 mi
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Let's say that the diameter was 1/2 mile. So the diameter is 1/2,  then you need to find the circumference, aka perimeter of the circle. So 1/2 times 3.14 = 1.57 miles So then you would do 1.57/2 = .785 of an hour If you round to nearest tenth The answer is .8 of an hour.
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A small publishing company is planning to publish a new book. The production costs will include one-time fixed costs (such as ed
natka813 [3]
Production cost = one time cost + variable costs

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6 0
3 years ago
Sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).
Sever21 [200]
\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta

\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}

Since \alpha lies in quadrant II, we have \cos\alpha, so

\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}

\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}

\beta lies in quadrant I, so \sin\beta>0 and

\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}

So

\sin(\alpha-\beta)=\dfrac{21}{29}\dfrac{15}{17}-\left(-\dfrac{20}{29}\right)\dfrac8{17}=\dfrac{475}{493}
8 0
3 years ago
If m∠WXY =160, what are m∠WXZ and m∠ZXY
Dominik [7]

Answer:

so it would be (7x-4)+(5x+8) = 160

x=13

4 0
3 years ago
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