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Damm [24]
3 years ago
7

Help me please please

Mathematics
1 answer:
Anna007 [38]3 years ago
5 0

Answer:

8/5 or 1.6

Step-by-step explanation:

Rise over run.

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Evaluate 3 - 24 = 8 + 4^2.<br> A 0<br> B 2<br> C 16<br> D 24
oee [108]

Answer:

-21=24

Step-by-step explanation:

Subtract 24 from 3

-21=8+2^2

Raise 4 to the power of 2

-21=8+16

Add 8 and 16

-21=24

7 0
3 years ago
Pls i need help with this geometry problem. Its due today .
ycow [4]

Answer:

63

Step-by-step explanation:

Set up the proportion

(6x+3)/17 = (8x - 1)/21                 Cross Multiply

21 * (6x + 3) = 17 (8x - 1)             Remove the brackets

126x + 63 = 136x - 17                 Subtract 126x from both sides

63 = 136x - 126x - 17                 Combine

63 = 10x - 17                              Add 17 to both sides

63 + 17 = 10x                             Combine the left

80        = 10 x                             Divide by 10

80/10 = x

x = 8

Now you want 8x - 1

8*8 - 1 = 63                

3 0
3 years ago
Find the lowest common denominator of the following fractions. 5/n-2 and n+2/n^2-4
Damm [24]
The denominator of the second fraction is the difference of squares, so can be factored using the formula for that.
  (n^2 -4) = (n -2)(n +2)

Now, you will note that the second fraction has a numerator that is equal to one of the factors in the denominator. In other words, the whole fraction can be simplified to ...
  (n +2)/((n +2)(n -2)) = 1/(n -2) . . . . with the restriction n≠-2

This reduced form of the fraction has the same denominator as the first fraction, so you can say that the lowest common denominator is that: (n -2).


_____
If there is some reason you don't want to reduce the second fraction, the lowest common denominator will be (n -2)(n +2).
6 0
3 years ago
Which series of transformations shows that pentagon A is congruent to pentagon B?
Fantom [35]
The <u>correct answer</u> is:

B) A 90° counterclockwise rotation about the origin, followed by a reflection across the x-axis, followed by a translation 8 units right and 1 unit up.

Explanation:

The coordinates of the <u>points of the pre-image</u> are:
(3, 1)
(3, 4)
(5, 7)
(6, 5)
(6, 2)

The coordinates of the <u>points of the image</u> are:
(7,-2)
(4,-2)
(1,-4)
(3,-5)
(6,-5)

A 90° counterclockwise rotation about the origin negates the y-coordinate and switches it and the x-coordinate.  Algebraically,
(x,y)→(-y,x).

When this is applied to our points, we get:
(3, 1)→(-1, 3)
(3, 4)→(-4, 3)
(5, 7)→(-7, 5)
(6, 5)→(-5, 6)
(6, 2)→(-2, 6)

A reflection across the x-axis negates the y-coordinate.  Algebraically,
(x, y)→(x, -y).

Applying this to our new points, we have:
(-1, 3)→(-1, -3)
(-4, 3)→(-4, -3)
(-7, 5)→(-7, -5)
(-5, 6)→(-5, -6)
(-2, 6)→(-2, -6)

A translation 8 units right and 1 unit up adds 8 to the x-coordinate and 1 to the y-coordinate.  Algebraically,
(x, y)→(x+8, y+1).

Applying this to our new points, we have:
(-1, -3)→(-1+8,-3+1) = (7, -2)
(-4, -3)→(-4+8,-3+1) = (4, -2)
(-7, -5)→(-7+8,-5+1) = (1, -4)
(-5, -6)→(-5+8,-6+1) = (3, -5)
(-2, -6)→(-2+8,-6+1) = (6, -5)

These match the coordinates of the image, so this is the correct series of transformations.
3 0
4 years ago
Can someone help me with Volume pyramids..​
Minchanka [31]

Answer:

\large\boxed{V=\dfrac{125}{3}\ cm^3=41\dfrac{2}{3}\ cm^3}

Step-by-step explanation:

The formula of a volume of a pyramid:

V=\dfrac{1}{3}BH

<em>B</em><em> - area of a base</em>

<em>H</em><em> - height</em>

We have

B=5\cdot5=25\ cm^2

H=5\ cm

Substitute:

V=\dfrac{1}{3}(25)(5)=\dfrac{125}{3}=41\dfrac{2}{3}\ cm^3

4 0
3 years ago
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