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OLEGan [10]
3 years ago
6

If y varies directly as x^2 and y=12 when x=2, find y when x=5

Mathematics
1 answer:
Shkiper50 [21]3 years ago
7 0
y=ax^2\\\\y=12\ \ \ and\ \ \ x=2\ \ \ \Rightarrow\ \ \ 12=a\cdot 2^2\ \ \ \Rightarrow\ \ \ a= \frac{4}{12}= \frac{1}{3}  \\\\y=\frac{1}{3} x^2\\\\x=5\ \ \ \Rightarrow\ \ \ y=\frac{1}{3} \cdot5^2=\frac{25}{3} =8\frac{1}{3}
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