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dem82 [27]
2 years ago
11

PLEASEEEEEE AWNSER I NEED HELP! (AWNSER in scientific notation) 24-27

Mathematics
1 answer:
N76 [4]2 years ago
5 0

Answer:

24 - 27 = -3

<em>and if you meant 2/4 - 2/7 in scientic notation:</em>

<em />

<em>2/4 - 2/7 = 3/14</em>

HOPE THIS HELPS

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The square ABCD has side length 20 cm,
bogdanovich [222]

Answer:

AE=22.4

Step-by-step explanation:

BE is 1/2 of BC

BC is 20 cm                 All sides of a square are equal

BE = 1/2 BC                  Property of a midpoint.

BE = 10

Now just use Pythagorus

AB^2 + BE^2 = AE^2

AE^2 = 20^2 + 10^2   Perform the sqrs

AE^2 = 400 + 100      Add the terms

AE^2 = 500                Take the square root of both sides

√AE^2 = √500

AE = 22.36

AE ≈ 22.4

6 0
2 years ago
Evaluate the quantity 3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two.
chubhunter [2.5K]

The value of the expression given as  [3² * 3⁻⁵]/[5⁻²] is 25/27

<h3>How to evaluate the expression?</h3>

The expression is given as:

3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two

Rewrite properly as:

[3² * 3⁻⁵]/[5⁻²]

Apply the negative exponent law of indices

So, we have

[3² * 3⁻⁵]/[5⁻²] = [5²]/[3⁻² * 3⁵]

Apply the exponent law of indices

[3² * 3⁻⁵]/[5⁻²] = [5²]/[3³]

This gives

[3² * 3⁻⁵]/[5⁻²] = 25/27

Hence, the value of the expression given as  [3² * 3⁻⁵]/[5⁻²] is 25/27

Read more about expressions at:

brainly.com/question/723406

#SPJ1

7 0
1 year ago
The money raised By $15 candy is approximately What percent of The total money raised from The candy sale
Monica [59]
Can you explain it a bit more?
7 0
3 years ago
Read 2 more answers
PLEASE HELP ME ON THIS
cricket20 [7]
The answer is 96. just multiply 6 *2 =12*2=24*2=48*2=96
5 0
3 years ago
Read 2 more answers
Graph the image of the figure using the transformation given. Don't forget prime marks on your new image. Part 1: reflection acr
amm1812

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , then

J (1, 4 ) → J' (- 1, 4 )

K (1, 0 ) → K' (- 1, 0 )

L (4, 3 ) → L' (- 4, 3 )

Plot the points J', K', L' and connect them in order to obtain image

4 0
3 years ago
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