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alexandr402 [8]

3 years ago

8

Total crimes 21,790,654. Roberry is 408, 016 and Burglary is 2,050,992 What are their percent in crimes rounded to the nearest p

ercent for each two crimes

1 answer:

RSB [31]3 years ago

8 0

Answer:

Percent of Robbery $=2 \%$

Percent of Robbery $=9 \%$

Step-by-step explanation:

Given that total number of crimes = 21,790,654.

total number of Robbery = 408, 016 and

total number of Burglary = 2,050,992

Now we need to find about what are their percent in crimes rounded to the nearest percent for each two crimes.

So apply the percent formula

$Percent=\frac{Part}{Whole}\times 100 \%$

Then percent of Robbery $=\frac{408016}{21790654}\times 100 \%=0.01872\times 100 \%=2 \%$

Then percent of Robbery $=\frac{2050992}{21790654}\times 100 \%=0.094122\times 100 \%=9 \%$

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5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

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