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3 years ago

Which equation could represent Relationship A?

Mathematics

2 answers:

AleksAgata [21]3 years ago

8 0

Hahshddhhddbjddjdjxdjdjfj

Dahasolnce [82]3 years ago

7 0

It would be the second and third one. The slope of B is 18.25 so A is less than B

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Approximately 4.7× 10^7 disposable diapers are thrown away each day in the United states.how many are thrown away each year?

Aleonysh [2.5K]

ANSWER:

17,155,000,000

STEP BY STEP:

4.7x10^7

4.7x10,000,000

47,000,000

47,000,000x365

17,155,000,000

5 0

3 years ago

Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti

natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

$f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5$

Simplifying:

$f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}$

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

$P(A) = \int_{5}^{15} = \frac{375}{t^4}$

Integral of $\frac{1}{t^4} = t^{-4}$ is $\frac{t^{-3}}{-3} = -\frac{1}{3t^3}$

Then

$\int \frac{375}{t^4} dt = -\frac{125}{t^3}$

Applying the limits, by the Fundamental Theorem of Calculus:

At $t = 15$ , $f(15) = -\frac{125}{15^3} = -\frac{1}{27}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}$

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

$P(B) = \int_{5}^{10} = \frac{375}{t^4}$

We already have the integral, so just apply the limits:

At $t = 10$ , $f(10) = -\frac{125}{10^3} = -\frac{1}{8}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}$

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087$

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

3 0

3 years ago

(6×1,000)+(1×100)+(2×10)+(9× 10 1 )+(4× 100 1 )=?

stiv31 [10]

Answer:

11033

Step-by-step explanation:

3 0

2 years ago

What process do you use to find the percent change of a quantity

Zigmanuir [339]

Find the amount of change by subtracting the two quantities. Divide this number by the original (starting) quantity, and convert to percent form by moving the decimal 2 places to the right.

8 0

3 years ago

Read 2 more answers

(8x-16)/x^2-13x+22 simpifyed completly

Veronika [31]

Answer:

3. 8 over x minus 11 , x ≠ 11

Step-by-step explanation:

(8x-16)/(x²-13x+22) =
8(x-2)/(x² - 2x - 11x + 22) =
8(x - 2)/(x - 2)(x - 11) =
8/(x - 11)

6 0

3 years ago