Answer:
8 cm
Step-by-step explanation:
Ok lets on the biggest square we have 17 cm
17cm is the hypotenuse for the right triangle
The second largest's area is 225 cm^2
Sq root of 225 cm^2, is 15
To find x, lets plug the info we have to the pythagorean theorom

The side length of the smallest Square is 8 cm
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Answer:
Step-by-step explanation:
b)
Answer:
The steady state proportion for the U (uninvolved) fraction is 0.4.
Step-by-step explanation:
This can be modeled as a Markov chain, with two states:
U: uninvolved
M: matched
The transitions probability matrix is:

The steady state is that satisfies this product of matrixs:
![[\pi] \cdot [P]=[\pi]](https://tex.z-dn.net/?f=%5B%5Cpi%5D%20%5Ccdot%20%5BP%5D%3D%5B%5Cpi%5D)
being π the matrix of steady-state proportions and P the transition matrix.
If we multiply, we have:

Now we have to solve this equations

We choose one of the equations and solve:

Then, the steady state proportion for the U (uninvolved) fraction is 0.4.
Answer:
The height of the triangle is 7cm and the base is 16cm
Step-by-step explanation:
First of all we have to know the formula to calculate area of a triangle
a = area = 56
b = base
h = heigth
a = (b * h)/2
we replace the known values and we make 2 equations
56cm² = (b * h)/2
b = h + 9cm
we replace b by (h + 9cm) in the first equation
56cm² = (h + 9cm * h)/2
56cm² * 2 = h² + 9h
0 = h² + 9h - 112cm²
we use bhaskara formula:
(-b (±) √
(b² - 4ac) ) / 2a
we replace with the known values
h = (-9 (±) √
(9² - 4*1*(-112) ) ) / 2*1
h = (-9 (±) √
(81 + 448) ) ) / 2
h = (-9 (±) √529) /2
h = (-9 (±) 23)/2
h1 = (-9 + 23) / 2
h1 = 14 / 2
h1 = 7
h2 = (-9 - 23) / 2
h2 = -32 / 2
h2 = -16
The height of the triangle is 7cm and the base is 16cm
Answer:
Step-by-step explanation:
you have to add all the fractions to find the perimeter
10 1/7+10 1/7= 20 2/7 (width)
20 2/7+35 3/7(length) =55 5/7
12 2/7+12 2/7=24 4/7
55 5/7+24 4/7= 79 9/7=80 2/7
80 2/7+ 15 3/14+ 24 1/14= 562/7+ 213/14+337/14= (1124+213+337)/14
=1674/14=119 8/14= 119 4/7