Answer:
D) < 3, 7)>
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given that the vector < 3 , -7 >
Given the vector reflection across the x-axis
(x,y) → (x , -y)
The vector < 3,-7> →< 3, -(-7)>
< 3,-7> →< 3, 7)>
Answer:
Step-by-step explanation:
While some might feel that online learning is the fun leisurely form of schooling that grants tons of free time, it honestly gets old quick. Being in quarantine makes it all the more worse because you do nothing all day. On the subject of math though, it is a disservice to have to learn math online. Personally, it is my experience that having a physical teacher and classroom to learn with is crucial to ones mathematical ability, but it's not the end of the world, it won't last long and it won't affect you that bad. Sure, the benefits include having more control over your day which is a good source of preparation for college life and responsibilities of being an adult, but you lose daily interpersonal interactions and typical casual daily exercise, since you no longer walk to class. Nevertheless, we will push on.
Answer:
B
Step-by-step explanation:
For a relationship to be a function
Each value of x in the domain can only have 1 unique value of y in the range. That is, one-to-one correspondence.
The only relation which meets this criteria is B
Answer: The approximate absentee rate that day would be 8.09%.
Step-by-step explanation:
Since we have given that
Number of students who were absent = 36
Total number of students = 445
We need to find the approximate absentee rate that day :
Rate of absentee of that day would be
Hence, the approximate absentee rate that day would be 8.09%.
Answer: The first 6 terms are = 8, 10, 12,14,16,18
Step-by-step explanation:
The NTH term of an Arithmetic Sequence is given as
an = a1 + (n - 1 ) d
where a1 = First term given as 8 and
d= common difference given as 2
Therefore We have that
the first term
an = a1 + (n - 1 ) d = 8+(1-1) 2
a1= 8
second term=
an = a1 + (n - 1 ) d= a2= 8 + (2-1) 2
= 8+ 2(1) = 10
3rd term
an = a1 + (n - 1 ) d= a3= 8 + (3-1) 2
= 8+ 2(2)= 8 + 4=12
4th term
an = a1 + (n - 1 ) d= a4= 8 + (4-1) 2
= 8+ 2(3)= 8+6=14
5th term
an = a1 + (n - 1 ) d= a5= 8 + (5-1) 2
= 8+ 2(4)=8+ 8=16
6th term
an = a1 + (n - 1 ) d= a6= 8 + (6-1) 2
= 8+ 2(5)=8 +10 =18
