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Debora [2.8K]
3 years ago
6

PLEASE HELP ASAP RNNNN

Mathematics
2 answers:
Solnce55 [7]3 years ago
5 0
DDDDDDDDD I think I’m srry if I’m wrong
Andrews [41]3 years ago
3 0

Answer:

Step-by-step explanation: b I think

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83 tens times 2 tens
gizmo_the_mogwai [7]

Answer:

16600 should be the answer.

Step-by-step explanation:

because 830 times 20 is 16600.

hope i helped

6 0
3 years ago
Given that QRST is a parallelogram, find the angle measures:
Mamont248 [21]

Answer:

below

Step-by-step explanation:

consecutive angles are supplementary in parallelogram

q+t = 180

3x+5+9x-17 = 180

12x-12 = 180

x-1 = 15

x=16

r=t = 127°

q=s = 53°

4 0
3 years ago
Read 2 more answers
What times what equals -42 but those same numbers added equals 1
Wittaler [7]

Answer:7 x -6

Step-by-step explanation: 7 x -6= -42

         7 + -6= 1

becasue different signs subtract and keep the sign of the bigger number since the 7 is positive and 6 is negative u subtrac and 7 is bigger than 6 so the answer is gonna be positive. Hope this was helpful <3

5 0
3 years ago
Which number is the missing amount of minutes for 4 miles from the equal ratio table below?
cluponka [151]

ERROR:  You forgot your attachment. Ask a new question and try again. :/

5 0
2 years ago
Read 2 more answers
The lifetime, in years, of some electronic component is a continuous random variable with the density f(x) =   k x4 for x ≥ 1
yuradex [85]

I suppose the density is supposed to be

f(x)=\begin{cases}\frac k{x^4}&\text{for }x\ge1\\0&\text{otherwise}\end{cases}

(since kx^4 diverges as x\to\infty, and 0 is conveniently left out of the domain)

For this to be a proper density function, it must be positive (it is) and its integral over the support [1,\infty) must evaluate to 1. We have

\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=\int_1^\infty\frac k{x^4}\,\mathrm dx=-\frac k{3x^3}\bigg|_1^\infty=\frac k3=1

which means k=3.

The distribution function is obtained by integrating the density:

F(x)=\displaystyle\int_{-\infty}^xf(t)\,\mathrm dt=\begin{cases}0&\text{for }x

The probability that the component exceeds 2 years in its lifetime is

P(X>2)=1-P(X\le 2)=1-F(2)=1-\left(1-\dfrac18\right)=\dfrac18

3 0
3 years ago
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