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bonufazy [111]
3 years ago
9

Describe all possible locations for the graph of (x,y) if x=2

Mathematics
1 answer:
jarptica [38.1K]3 years ago
7 0
There are infinite solutions to this , so and coordinate with than x value of 2 will lie on x=2
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Graph the inequality below on the number line.
marshall27 [118]

Answer:

You start at -9

-Open circle

-shade towards the right (where all the positive numbers are)

Open circle - ones that don't have a greater than or equal to. If it does then it's a closed one.

Shade towards the right cause y is less than 9

3 0
3 years ago
Read 2 more answers
On a coordinate plane, triangle A B C is shown. Point A is at (negative 1, 1), point B is at (3, 2), and points C is at (negativ
oksian1 [2.3K]

The corresponding height of the triangle is 1.6 units

The formula for calculating the area of a triangle is expressed as:

A=\frac{1}{2} bh

  • b is the base of the triangle
  • h is the height of the triangle

Given the coordinates of the base BC of the triangle given as B(3, 2), and C(-1,-1). Using the distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\BC= \sqrt{(-1-2)^2+(-1-3)^2}\\BC=\sqrt{3^2+4^2}\\BC=\sqrt{25}\\BC=5units

The area of the triangle passing through the coordinate points A(-1, 1), B(3,2), and C(-1, -1) is expressed as:

A=\frac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]\\

Substituting the coordinate points:

A=\frac{1}{2}[(-1)(2-(-1))+3(-1-1)+-1(1-2)]\\A=\frac{1}{2}[(-1)(3)+3(-2)+-1(-1)]\\A=\frac{1}{2}[-3-6+1]\\A=\frac{1}{2} (-8)\\|A| =4 units^2

Recall that:

A = 0.5bh\\h=\frac{A}{0.5b}\\h=\frac{4}{0.5(5)}\\h=\frac{4}{2.5}\\h=   1.6 units

Hence the corresponding height of the triangle is 1.6 units

Learn more on area of triangles here: brainly.com/question/17335144

8 0
3 years ago
If the FDIC has a $59.5 billion insurance fund and must use 5.6% of it to cover several failed banks, approximately how much mon
Sonja [21]
<span>The answer is a. $56.17 billion</span>
4 0
3 years ago
Read 2 more answers
If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?
Rufina [12.5K]
x is in quadrant I, so 0, which means 0, so \dfrac x2 belongs to the same quadrant.

Now,

\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}

Since \sin x=\dfrac5{13}, it follows that

\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}

Since x belongs to the first quadrant, you take the positive root (\cos x>0 for x in quadrant I). Then

\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}

\tan x is also positive for x in quadrant I, so you take the positive root again. You're left with

\tan\dfrac x2=\dfrac15
4 0
3 years ago
PLZ HELP ME PLZZZ 15 PTS Mr. Rodriguez asked 60 randomly chosen students from each grade level at Willowbrook School about their
vredina [299]
12/60 students chose science fiction

Approximately x/150 students prefer sf

60x = 1800

x = 30

30/150 students are assumed to prefer sf

30/150 = x/100

150x = 3000

x = 20

20/100 students are likely to prefer sf

Mr. Rodriguez made a reasonable estimate for the approximate percentage of students that prefer science fiction, because if 12/60 is equivalent to 30/150 which refers to the number of students who can be assumed to prefer science Fiction out of the whole school. Considering we need to identify what 30/150 as a percentage is, we can reduce it down to 1/5 to make I easier, then divide 1 by 5 to get .2
.2 as a percentage is 20%, so his inference was indeed reasonable.

(♥ω♥*)Brainliest Please(♥ω♥*)

8 0
3 years ago
Read 2 more answers
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