Use the identity
sec^2x = 1 + tan^2 x
- so sec x = sqrt(1 + tan^2 x) then:-
tan x + sqrt( 1 + tan^2 x) = 1
sqrt ( 1 + tan^2 x) = 1 - tan x
1 + tan^2 x = 1 + tan^2x - 2 tan x
0 = -2 tanx
tan x = 0
x = 0, π
π is an extraneous root because sec 180 = -1
So the answer is 0 degrees
Simple.....
All you have to do is simplify the radical by breaking the radicand up into a product of known factors.
Thus, your answer.
Answer:
x>3
Step-by-step explanation:
8x-6>12+2x
Subtract 2x from each side
8x-2x-6>12+2x-2x
6x -6 > 12
Add 6 to each side
6x-6 +6 > 12+6
6x> 18
Divide each side by 6
6x/6 >18/6
x>3
Answer:
I DO NOT UNDRESTAND THE QUESTION.