Answer:
Please check the explanation.
Step-by-step explanation:
- As we know that the values in the table represent a function only if there there is only 1 input for every output.
Given the table 1
x y
-12 2
-10 10
0 -2
5 -6
8 -11
15 -15
From the table, it is clear that for each input there exists a unique output.
i.e.
According to the given table,
y = 2 at x=-12
y = 10 at x=-1
0
y = -1 at x=0
y = -11 at x=8
y = -15 at x=15
From the table, it is clear that for each input x, it has a unique output y.
Hence, table 1 is a function.
Given the table 2
x y
9 -18
-20 0
-6 1
-17 16
9 17
11 19
This table does not produce a function, because the input x=9 produces two outputs.
i.e.
at x = 9, the y = -18
at x = 9, the y = 17
Therefore, the table 2 does not represent a function.
Answer:
y=12
Step-by-step explanation:
Use order of operations. Subtract 18 from both sides and the divide by 2.
2y+18 -18=42-18
2y=24
y=12
Answer:
Two points on the graph would be (2,-1) and (4,2).
Step-by-step explanation:
You can choose two random x variables such as how i selected 2 and 4. if you change the variable x to those values you can solve for y or in this case f(x).
EX:
3/2*2-4
6/2-4
3-4
f(x)= -1
Answer:
Systolic on right
Systolic on left
So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.
Step-by-step explanation:
Assuming the following data:
Systolic (#'s on right) Diastolic (#'s on left)
117; 80
126; 77
158; 76
96; 51
157; 90
122; 89
116; 60
134; 64
127; 72
122; 83
The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:
And the best estimator is
Systolic on right
We can calculate the mean and deviation with the following formulas:
[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]
For this case we have the following values:
So then the coeffcient of variation is given by:
Systolic on left
For this case we have the following values:
So then the coeffcient of variation is given by:
So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.